Implementing Equation in matlab
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I have to implement park transformation ,the input to park transformation is
Va,Vb,Vc and theta and output is Vq,please tell how to implement this block
7 个评论
Azzi Abdelmalek
2012-12-28
Are you using simulink?
FIR
2012-12-28
@FIR: As usual I ask, what you have done so far and which problems have occurred. And again I add the "doit4me" tag, because I do not see any own effort or that you've spent enough time and energy to make your question clear.
An impressing large number of your question is marked by doit4me tags. Doesn't this let you think twice if you are perhaps trying to abuse this forum to do your work?
FIR
2012-12-28
Jan
2012-12-28
@FIR: Do you think, that you make answering your questions as easy as possible? You did not answer a lot of questions for clarifications in the past. More than 50% of your questions could not be answered sufficiently.
FIR
2012-12-28
Image Analyst
2013-1-5
Out of 200 questions you've asked, you've accepted only 47% of them (as shown in your profile). Does that mean we have a 53% chance of wasting both your time and our time if we spend time helping you?
采纳的回答
Azzi Abdelmalek
2012-12-28
编辑：Azzi Abdelmalek
2012-12-28
0 个投票
You can use Matlab function block or Interpreted Matlab Function block to implement your abc-dq transformation
8 个评论
FIR
2012-12-28
Azzi Abdelmalek
2012-12-28
The image just show the transformation matrix. You have to read basis of Park transformation http://en.wikipedia.org/wiki/Dqo_transformation
FIR
2013-1-4
Azzi Abdelmalek
2013-1-4
FIR, you don't need a two blocks abc-alfa,beta then alfa,beta-dq, you can use one block abc-dq, with 4 inputs ua, ub, uc, the angle theta and two outputs ud, uq. You just need to get the Park transformation matrix, and use a matlab function block to make your program.
FIR
2013-1-5
Azzi Abdelmalek
2013-1-5
编辑：Azzi Abdelmalek
2013-1-5
This is exact. But you can simply use one block instead all those blocks. a matlab function block with a function
function [ud,uq]=fcn(ua,ub,uc,tetas)
uq=sqrt(2/3)*(cos(tetas)*ua+cos(tetas-2*pi/3)*ub+cos(tetas-4*pi/3)*uc);
ud=sqrt(2/3)*(-sin(tetas)*ua-sin(tetas-2*pi/3)*ub-sin(tetas-4*pi/3)*uc);
The gain 2/3 or sqrt(2/3) depends on the Park transformation you've chosen.
FIR
2013-1-5
Azzi Abdelmalek
2013-1-5
FIR, I think it was clear how to program a Park transformation block, by the blocks you found or by the block I suggested. Maybe you have some problem with theory, I think you should read this theory.
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