plot curves in matlab

Question

saman ahmadi 2020-8-15

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/579978-plot-curves-in-matlab

编辑： John D'Errico 2020-8-15

Hi. How can i plot below equation(qa vs w)?

thank you

(9*w^4*cos(qa))/28000000 - (33*w^2*cos(qa))/32000 - (105*cos(qa))/64 + (603*w^2)/2560000 - (4891*w^4)/4480000000 + (93*w^6)/560000000000 + 105/64=0

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Answer 1

John D'Errico 2020-8-15

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https://ww2.mathworks.cn/matlabcentral/answers/579978-plot-curves-in-matlab#answer_480306

编辑：John D'Errico 2020-8-15

在 MATLAB Online 中打开

fun = @(w,qa) (9*w.^4.*cos(qa))/28000000 - (33*w.^2.*cos(qa))/32000 - (105*cos(qa))/64 + (603*w.^2)/2560000 - (4891*w.^4)/4480000000 + (93*w.^6)/560000000000 + 105/64;
fimplicit(fun)

You can tell fimplicit how far out to go of course.

fimplicit(fun,[-100 100 -100 100])

It does appear as if much is happening when you broaden the view.

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saman ahmadi 2020-8-15

56666.JPG

thanks. from plotting sended equation must plot a curve like image attachmented.

John D'Errico 2020-8-15

编辑：John D'Errico 2020-8-15

在 MATLAB Online 中打开

Sigh. It would have helped if you asked that question in the first place, instead of just asking how to plot qa as a function of w.

fun = @(qa,w) (9*w.^4.*cos(qa))/28000000 - (33*w.^2.*cos(qa))/32000 - (105*cos(qa))/64 + (603*w.^2)/2560000 - (4891*w.^4)/4480000000 + (93*w.^6)/560000000000 + 105/64;
fimplicit(fun,[-pi pi 0 100])

If you are looking for a specific result, then you need to tell people. That seems to come pretty close, though the scaling of the variables seems to be different from the plot you show. That is more a question of the specific function you gave us, which is surely different from that which generated your plot.

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Answer 2

Alan Stevens 2020-8-15

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/579978-plot-curves-in-matlab#answer_480312

在 MATLAB Online 中打开

Somethig like this:

qafn = @(w) acos(( 4891*w.^4/4480000000 -93*w.^6/560000000000 -603*w.^2/2560000 -105/64 )...
    ./(9*w.^4/28000000 - 33*w.^2/32000 - 105/64 ));
w = -50:50;
qa = qafn(w);
plot(w,qa)

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Alan Stevens 2020-8-15

编辑：Alan Stevens 2020-8-15

在 MATLAB Online 中打开

Looks like the implicit function is the way to go, though the w axis is scaled differently.

qawfn = @(qa,w) (9*w.^4.*cos(qa))/28000000 - (33*w.^2.*cos(qa))/32000 - (105*cos(qa))/64 ...
+ (603*w.^2)/2560000 - (4891*w.^4)/4480000000 + (93*w.^6)/560000000000 + 105/64;
fimplicit(qawfn,[-pi pi 0  90])