Loading digit from big number

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ZK 2013-1-10

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Hi, I have another question. I have a big number something like 200308091234562. I would like to appeal to indicated parts. To other calculations.

So I would like to have something like this from this big number.

A = 2003 B = 08 C = 09 D = 123

Which funtion should I use. Thank You.

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ZK 2013-1-10

编辑：ZK 2013-1-10

It is loaded by textread from document. Leading zero means that this is August.

Jan 2013-1-10

@ZK: Please post the type of the variable, which contains the shown value. Use the Matlab command class() to find out the type in case of doubt. Numbers do not have a leading zero and in '08' it is surely not the '0' which indicates that it is August, but the '8'.

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Answer 1

Andreas Goser 2013-1-10

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编辑：Andreas Goser 2013-1-10

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I suggest treating this numerical value as a string ('chararcter array') and us such operations, e.g.

s='200308091234562'
A=s(1:4)

Maybe you want to do math with it afterwards:

str2num(A)*2

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Answer 2

Jan 2013-1-10

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If 200308091234562 is a double:

d = 200308091234562
A = floor(d / 1e11);
B = rem(floor(d / 1e9), 100);
C = rem(floor(d / 1e7), 100);
D = rem(floor(d / 1e4), 1000);

If the value is a string:

s = '200308091234562'
A = s(1:4);
B = s(5:6);
C = s(7:8);
D = s(9:11);

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Jan 2013-1-10

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Dear ZK, I've presented two different solutions. Therefore "this is it" does not reveal in which format the data are available. Instead of clarifying this, you ask the next question, whose answer require the knowledge of the actual format again. "textread read it as 1x1 cell" is a vague description again, which requires to guess the details.

I suggest the following pattern:

 My file contains lines like:
  200308091234562
  200308099812348
  200308012803753
 I read it with:
  data = textread(fid, '%s');
 Now I get a {1x1} cell, which contains a cell string:
  data = {{'200308091234562', '200308099812348', '200308012803753'}}
 I want to get:
  A = 2003;   % or '2003' ?
  B = 8;      % or '08' ?
  C = 9;
  D = 123;