Subscripted assignment dimension mismatch.

1 次查看（过去 30 天）
Jacob Moses
Jacob Moses 2013-1-12
Hello, I am attempting to separate a large matrix into two parts for kernel formation for clustering with a kernel k-means algorithm. While I would ordinarily jus reshape it into a third dimension, this option is impossible given that the number of columns in the matrix in question is odd (24021). I have been unable to perform any of the things that I have seen before, such as indexing. Below is the method I tried, which returned the above error message.
EDU>> for n=1:24041
if n<=12021
split{1}(n)=test(:,n);
elseif n>12021
split{2}(n-12021)=test(:,n)
end
end
Subscripted assignment dimension mismatch.
If anyone can tell me what is going on, I would greatly appreciate it. Thanks in advance.

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2013-1-12
split{1} = test(:,1:12021);
split{2} = test(:,12022:end);
  1 个评论
Jacob Moses
Jacob Moses 2013-1-12
This worked perfectly, and was easiest for me to understand. Thank you so much!

请先登录，再进行评论。

更多回答（1 个）

José-Luis
José-Luis 2013-1-12
编辑：José-Luis 2013-1-12
You are probably trying to assign a matrix to a scalar:
split{1}(n)=test(:,n);
split{1}(n) is most likely a scalar
test(:,n) is probably a column vector

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by