Store values generate in a function call in an array
显示 更早的评论
Hi I am trying to store the coordinates of the 4 spheres I am plotting from a function call. I can only return the final spheres coordinates instead of all of them. Any help would be greatly appreciated.
xyz = [-8.67212090030965 -7.78294481282592 4.19809966191787
4.30363429770975 -6.33796132936349 2.30412196271579
11.4626419696253 3.31049523749869 2.84193335035400
1.28757516363600 6.20802478748340 11.1358580308193];
x1 = xyz(:, 1);
y1 = xyz(:, 2);
z1 = xyz(:, 3);
SizeXYZ = size(xyz,1);
for i = 1:SizeXYZ
[x,y,z spheresXYZ] = createspheres(x1(i),y1(i),z1(i));
surf(x,y,z,'FaceColor', 'k');
hold on
end
%
function [X,Y,Z, spheresXYZ] =createspheres(spherex, spherey, spherez)
[x, y, z] = sphere(4);
X = x+spherex;
Y = y+spherey;
Z = z+spherez;
spheresXYZ = [X,Y,Z];
end
2 个评论
Rik
2020-9-2
I'm not sure I understand what you mean. Could you provide an example of what you want as the output?
Nnamdi Chukwunenye
2020-9-2
采纳的回答
Bruno Luong
2020-9-2
编辑：Bruno Luong
2020-9-2
spheresXYZ = cell(1,SizeXYZ);
for i = 1:SizeXYZ
[x,y,z spheresXYZ{i}] = createspheres(x1(i),y1(i),z1(i));
...
end
2 个评论
Nnamdi Chukwunenye
2020-9-2
Bruno Luong
2020-9-3
编辑：Bruno Luong
2020-9-3
If you prefer storage 3D array (assuming the function returns always a fixed size output) you can get them like this at the end of the loop
spheresXYZ = cell(1,SizeXYZ);
for i = 1:SizeXYZ
...
end
spheresXYZ = cat(3, spheresXYZ{:});
Then when needed, each sphere #k coordinates can be obtained by
spheresXYZ(:,:,k)
There is a whole bunch of techniques to preallocate nd array (see e.g. Rik's answer) that can be adapted for each case. This topic is beyond this thread.
更多回答（1 个）
Rik
2020-9-3
Instead of using a cell array, you can also use a 3D matrix:
[~,~,~,spheresXYZ]=createspheres(0,0,0);spheresXYZ(1,1,SizeXYZ)=0;
for n = 1:SizeXYZ
[x,y,z,spheresXYZ(:,:,n)] = createspheres(x1(n),y1(n),z1(n));
end
类别
在 帮助中心 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
