find the minimum value of y for positive vales of x
3 次查看(过去 30 天)
显示 更早的评论
i have xmin=min(y(x>0)); where x=[-100:100] & y =x^3+60x^2-50 it gives me -50 which is wrong
aloso i have xmin=min(y(0:x(end))); where x=[-100:100] & y =x^3+60x^2-50 it gives me -50 which is wrong answer
any ideas? is my expression wrong ?
采纳的回答
per isakson
2020-9-3
Try this
%%
x = (-100:100);
y = x.^3+60*(x.^2)-50;
%%
xmin = min(y(x>0))
which returns
xmin =
11
>>
0 个评论
更多回答(0 个)
另请参阅
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!