Multiple errors with derivative calculator code

Question

Kwasi Baryeh 2020-9-6

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/589672-multiple-errors-with-derivative-calculator-code

编辑： John D'Errico 2020-9-6

disp('This calculates a polynomial derivative at a specific point')
x = sym ('x');
 
g = input('What is your polynomial function?','s');
f() = str2func(['@(x)', 'g']);
 
a = input('What value would you like to derive it at?');
 
n = limit ((f(x) - f(a))/(x-a),a);
 
fprintf('The derivative of %s \n', f(x))
fprintf('at point %f is %f',n)

I get an error message here:

Error: File: DerivativeCalculator.m Line: 5 Column: 2

An indexing expression on the left side of an assignment must have at least one subscript.

What are the problems with my code?

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Answer 1

John D'Errico 2020-9-6

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/589672-multiple-errors-with-derivative-calculator-code#answer_490579

编辑：John D'Errico 2020-9-6

在 MATLAB Online 中打开

This is not valid syntax in MATLAB. It may be so in some other language. But not so here.

f() = str2func(['@(x)', 'g']);

As you can see,

g = 'x^2';
f() = str2func(['@(x)', 'g']);
 f() = str2func(['@(x)', 'g']);
  ↑
Error: An indexing expression on the left side of an assignment must have at least one subscript.

The error message tells you MATLAB did not like the f() on the left side of the assignment. The assignment operator in MATLAB is the = sign. To the left of that, MATLAB saw f(), but no index inside the ().

The answer is simple (besides learning MATLAB more completely) is to just write it as:

f = str2func(['@(x)', 'g']);

In MATLAB, f is a variable, that just happens to contain a function handle.

whos f
  Name      Size            Bytes  Class              Attributes
  f         1x1                32  function_handle              

You assign something into a variable like you assign any other variable.

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John D'Errico 2020-9-6

编辑：John D'Errico 2020-9-6

在 MATLAB Online 中打开

And that is because you did not use str2func properly.

What is g? (A string.) For example...

>> g = input('What is your polynomial function?','s');
What is your polynomial function?x^2
>> g
g =
    'x^2'

Now, when you tried to use str2func with g, what did you do?

>> f = str2func(['@(x)', 'g']);
>> f
f =
  function_handle with value:
    @(x)g

WRONG. How did you use g? You are confusing the variable name g, with a string 'g'. What the variable g contains is not the character string 'g'. And just because the variable itself contains a string, does not mean you will access that character string as 'g'.

Instead, you need to access what the variable g contains. Think of a variable as a container. Thus, what does g contain? At least in this case, g holds a character string form of the expression:

>> g
g =
    'x^2'

And now if we use g properly, we see:

>> f = str2func(['@(x) ', g]);
>> f
f =
  function_handle with value:
    @(x) x^2
    
>> f(2)
ans =
     4     

Now we see we can evaluate f at any point x. I perhaps should have written g as x.^2, in which case the function would be vectorized properly. But that is probably grist for your next homework assignment.

>> syms x
>> a = 2;
>> limit ((f(x) - f(a))/(x-a),a)
ans =
4

Kwasi Baryeh 2020-9-6

Thank you for your insight! This isn't for a homework assignment. I'm just starting out on MATHLAB with a school license and seeing what I can do with it. I'll look deeper at my code.

John D'Errico 2020-9-6

编辑：John D'Errico 2020-9-6

在 MATLAB Online 中打开

Just think about the difference between the name of a variable and what it contains.

Anyway, here is another way you could have performed the differentiation. You used the definition of a derivative as a limit there. But you could just have used diff.

>> g
g =
    'x^2'
    
>> gsym = str2sym(g)
gsym =
x^2

str2sym converts the string into a symbolic variable. So gsym contains essentially the same expression as g, but here it is stored in a different form. whos tells us this fact:

>> whos g gsym
  Name      Size            Bytes  Class    Attributes
  g         1x3                 6  char               
  gsym      1x1                 8  sym                

But now we can use symbolic tools on gsym.

>> gprime = diff(gsym,x)
gprime =
2*x

And finally we can turn gprime into a function we can evaluate directly.

f = matlabFunction(gprime)
f =
  function_handle with value:
    @(x)x.*2.0

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Multiple errors with derivative calculator code

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