Building a matrix with a varying column length

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Giorgos Papakonstantinou
I am trying to build a matrix whose rows are as many as the length of D (see below) and whose columns vary. Because this is impossible I tried to preallocate the size of the matrix trying to fill it with zeros. Unfortunately I get the following error:
Subscripted assignment dimension mismatch.
Below you can see my code
n=1:1:2;
D(:,1)=L./(2.*n);
% Wf=20*10^-6:10^-6:L;
% S=zeros(size(Wf));
Wfmin=20e-6;
Wf_step=1e-6;
Wfmax=2*max(D);
size=length(Wfmin:Wf_step:Wfmax);
for i=1:length(D)
Wf=zeros(i,size);
Wf(i,:)=20e-6:1e-6:2*D(i);
end

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采纳的回答

Walter Roberson
Walter Roberson 2013-1-24
T = 20e-6:1e-6:2*D(i);
Wf(i, 1:length(T)) = T;

更多回答（1 个）

Giorgos Papakonstantinou
Thank you Walter

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