Plotting a graph for a function with x <- seq(from=-2, to=2, len=10000) on the y axis and x on the x-axis

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Deepti Duvvuri
Deepti Duvvuri 2020-9-23
评论： Ameer Hamza 2020-9-24
Hi there,
I'm trying to convert code in R
f<- function(x) {(sin(sin(x^2)) + cos(x/(1+x+2*x^2)) -11/10)}
x <- seq(from=-2, to=2, len=10000)
plot(x,f(x), type='l')
abline(h=0)
to code in Matlab. I've tried a few options like fplot() but it doesn't work for a sequence.
How do I achieve this?
BTW, I'm new to both R & to Matlab
  1 个评论
Deepti Duvvuri
Deepti Duvvuri 2020-9-23
Thanks so much!! Is yline the same as abline? and how do I plot a vertical abline in Matlab? Is there any documentation that I could refer to? Thank you once again!!!

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Ameer Hamza
Ameer Hamza 2020-9-23
Something like this
f = @(x) (sin(sin(x.^2))+cos(x/(1+x+2*x.^2))-11/10);
x = linspace(-2, 2, 10000);
plot(x, f(x))
yline(0);
  2 个评论
Steven Lord
Steven Lord 2020-9-23
Instead of creating your own yline to simulate the X axis, you could change where the X axis is drawn. I don't know if this is more to the original poster's liking.
ax = gca; % or call plot with an output and use ancestor
ax.XAxisLocation = 'origin';

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