How to connect two displays?

Question

Minhao Wang 2020-9-25

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/599545-how-to-connect-two-displays

评论： Minhao Wang 2020-9-25

clc;clear
C1 = input('Please enter a code to break: ' , 's');
if length(C1) ~= 6
    disp('Decoy message: Not a six-digit number.');
else
    A = mod(sum(C1 - '0'),2);
end
    if A == 1
        disp('Decoy message: Sum is odd.')
    else
        C2 = (C1(1) - '0') * (C1(2) - '0') - (C1(3) - '0');
    end
    switch C2
        case 1  
            disp('Rescue on Monday')
        case 2
            disp('Rescue on Tuesday')
        case 3
            disp('Rescue on Wednesday')
        case 4 
            disp('Rescue on Thursday')
        case 5
            disp('Rescue on Friday')
        case 6 
            disp('Rescue on Saturday')
        case 7
            disp('Rescue on Sunday')
        otherwise
            disp('Decoy message:Invalid rescue day.');
    end
    F1 = str2num(C1(4));
    F2 = str2num(C1(5));
    F3 = str2num(C1(6));
if mod(F1,3) == 0
    B = F2 - F3;
else
    B = F3 - F2;
end
switch(B)
    case 1
        disp('at the bridge.');
    case 2
        disp('at the library.');
    case 3
        disp('at the river crossing.');
    case 4
        disp('at the airport.');
    case 5
        disp('at the bus terminal.');
    case 6
        disp('at the hospital.');
    case 7
        disp('at the St. Petes Church.');
    otherwise
        disp('Decoy message:Invalid rendezvous point.');
end

If we run this Script and enter 510129,it will appear:

Please enter a code to break: 510129

Rescue on Friday

at the St. Petes Church.

But I would like to make it appear :

Please enter a code to break: 510129

Rescue on Friday at the St. Petes Church.

How do I do that?

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Answer 1

KSSV 2020-9-25

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/599545-how-to-connect-two-displays#answer_500134

编辑：KSSV 2020-9-25

在 MATLAB Online 中打开

clc;clear
C1 = input('Please enter a code to break: ' , 's');
if length(C1) ~= 6
    disp('Decoy message: Not a six-digit number.');
else
    A = mod(sum(C1 - '0'),2);
end
    if A == 1
        disp('Decoy message: Sum is odd.')
    else
        C2 = (C1(1) - '0') * (C1(2) - '0') - (C1(3) - '0');
    end
    switch C2
        case 1  
            str1 = 'Rescue on Monday' ; 
        case 2
            str1 = 'Rescue on Tuesday' ; 
        case 3
            str1 = 'Rescue on Wednesday' ;
        case 4 
            str1 = 'Rescue on Thursday' ; 
        case 5
            str1 = 'Rescue on Friday' ; 
        case 6 
            str1 = 'Rescue on Saturday' ;
        case 7
            str1 = 'Rescue on Sunday' ;
        otherwise
            str1 = 'Decoy message:Invalid rescue day.' ;
    end
    F1 = str2num(C1(4));
    F2 = str2num(C1(5));
    F3 = str2num(C1(6));
if mod(F1,3) == 0
    B = F2 - F3;
else
    B = F3 - F2;
end
switch(B)
    case 1
        str2 = ('at the bridge.');
    case 2
        str2 = ('at the library.');
    case 3
        str2 = ('at the river crossing.');
    case 4
        str2 = ('at the airport.');
    case 5
        str2 = ('at the bus terminal.');
    case 6
        str2 = ('at the hospital.');
    case 7
        str2 = ('at the St. Petes Church.');
    otherwise
        str2 = ('Decoy message:Invalid rendezvous point.');
end
str = [str1,' ', str2] ; 
fprintf("%s\n",str) ; 