Finding Mean for Blocks of Image

4 次查看(过去 30 天)
Hi all,
I have a 1024x1024 gray image. I want to scan 32x32 pixels window from
top to bottom and left to right in order to find Mean value of each window.
How should i do this?

采纳的回答

Image Analyst
Image Analyst 2013-2-3
See this demo. It will be very easy for you to adapt it. Basically you do this:
meanFilterFunction = @(theBlockStructure) mean2(theBlockStructure.data(:)) * ones(2,2, class(theBlockStructure.data));
blockSize = [32 32];
blockyImage = blockproc(grayImage, blockSize, meanFilterFunction);
Here's the full demo:
% Demo code to divide the image up into 16 pixel by 16 pixel blocks
% and replace each pixel in the block by the median, mean, or standard
% deviation of all the gray levels of the pixels in the block.
%
clc;
clearvars;
close all;
workspace;
fontSize = 16;
% Read in a standard MATLAB gray scale demo image.
folder = fullfile(matlabroot, '\toolbox\images\imdemos');
if ~exist(folder, 'dir')
% If that folder does not exist, don't use a folder
% and hope it can find the image on the search path.
folder = [];
end
baseFileName = 'cameraman.tif';
fullFileName = fullfile(folder, baseFileName);
grayImage = imread(fullFileName);
% Get the dimensions of the image. numberOfColorBands should be = 1.
[rows columns numberOfColorBands] = size(grayImage)
% Display the original gray scale image.
subplot(2, 2, 1);
imshow(grayImage, []);
title('Original Grayscale Image', 'FontSize', fontSize);
% Enlarge figure to full screen.
set(gcf, 'Position', get(0,'Screensize'));
set(gcf,'name','Image Analysis Demo','numbertitle','off')
% Define the function that we will apply to each block.
% First in this demo we will take the median gray value in the block
% and create an equal size block where all pixels have the median value.
% Image will be the same size since we are using ones() and so for each block
% there will be a block of 8 by 8 output pixels.
medianFilterFunction = @(theBlockStructure) median(theBlockStructure.data(:)) * ones(size(theBlockStructure.data), class(theBlockStructure.data));
% Block process the image to replace every pixel in the
% 8 pixel by 8 pixel block by the median of the pixels in the block.
blockSize = [8 8];
% Quirk: must cast grayImage to single or double for it to work with median().
% blockyImage8 = blockproc(grayImage, blockSize, medianFilterFunction); % Doesn't work.
blockyImage8 = blockproc(single(grayImage), blockSize, medianFilterFunction); % Works.
[rows columns] = size(blockyImage8);
% Display the block median image.
subplot(2, 2, 2);
imshow(blockyImage8, []);
caption = sprintf('Block Median Image\n32 blocks. Input block size = 8, output block size = 8\n%d rows by %d columns', rows, columns);
title(caption, 'FontSize', fontSize);
% Block process the image to replace every pixel in the
% 4 pixel by 4 pixel block by the mean of the pixels in the block.
% The image is 256 pixels across which will give 256/4 = 64 blocks.
% Note that the size of the output block (2 by 2) does not need to be the size of the input block!
% Image will be the 128 x 128 since we are using ones(2, 2) and so for each of the 64 blocks across
% there will be a block of 2 by 2 output pixels, giving an output size of 64*2 = 128.
% We will still have 64 blocks across but each block will only be 2 output pixels across,
% even though we moved in steps of 4 pixels across the input image.
meanFilterFunction = @(theBlockStructure) mean2(theBlockStructure.data(:)) * ones(2,2, class(theBlockStructure.data));
blockSize = [4 4];
blockyImage64 = blockproc(grayImage, blockSize, meanFilterFunction);
[rows columns] = size(blockyImage64);
% Display the block mean image.
subplot(2, 2, 3);
imshow(blockyImage64, []);
caption = sprintf('Block Mean Image\n64 blocks. Input block size = 4, output block size = 2\n%d rows by %d columns', rows, columns);
title(caption, 'FontSize', fontSize);
% Block process the image to replace every pixel in the
% 8 pixel by 8 pixel block by the standard deviation
% of the pixels in the block.
% Image will be smaller since we are not using ones() and so for each block
% there will be just one output pixel, not a block of 8 by 8 output pixels.
blockSize = [8 8];
StDevFilterFunction = @(theBlockStructure) std(double(theBlockStructure.data(:)));
blockyImageSD = blockproc(grayImage, blockSize, StDevFilterFunction);
[rows columns] = size(blockyImageSD);
% Display the block standard deviation filtered image.
subplot(2, 2, 4);
imshow(blockyImageSD, []);
title('Standard Deviation Filtered Image', 'FontSize', fontSize);
caption = sprintf('Block Standard Deviation Filtered Image\n32 blocks. Input block size = 8, output block size = 1\n%d rows by %d columns', rows, columns);
title(caption, 'FontSize', fontSize);
  5 个评论
nissrine Neyy
nissrine Neyy 2021-12-10
Thank you for reply image analyst
I experemented with some images and checked the result values, in my case i devided an image of 80x120 pixel into 8x8 blocks and i want to calculate the mean of each block, i used the function to do that and i was curious to know why the "ones". So while exprementing the output was 16x16. i still don"t get the purpose of it since without the ones the result is 8x8 which is expected since we're calculating the mean and supposed to have one value for each block, and this specially if we'll be having more operations on the output image.
Image Analyst
Image Analyst 2021-12-10
I don't see any way you'd get an output of 16 by 16.
If you use a blocksize of 8 with an image of 80x120, and don't use the ones(), the result will be 10 by 15. NOT 8 by 8.
meanFilterFunction = @(theBlockStructure) mean2(theBlockStructure.data(:));
blockSize = [8, 8];
blockyImage = blockproc(grayImage, blockSize, meanFilterFunction);
How could it be giving you 8 by 8???? With 80 rows you can fit 10 tiles vertically and with 120 columns you can fit 15 tiles (of width 8) horizontally. so the output image should be 10x15, not 8x8.
If you want an output of 8x8 you'd need 8 tiles of height 10, and 8 tiles of width 120/8 = 15. And don't use ones. Then, with
meanFilterFunction = @(theBlockStructure) mean2(theBlockStructure.data(:));
blockSize = [10, 15];
blockyImage = blockproc(grayImage, blockSize, meanFilterFunction);
the output will be 8x8.

请先登录,再进行评论。

更多回答(2 个)

Jan
Jan 2013-2-12
img = rand(1024, 1024);
b = reshape(img, 32, 32, 32, 32);
m = squeeze(sum(sum(b, 1), 3) / (32*32));

neelavathi d
neelavathi d 2016-3-18
how to find the mean value for each block

类别

Help CenterFile Exchange 中查找有关 Computer Vision with Simulink 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by