0 个投票

I have a matrix 8314 x 3 and want to cut it down to 144 x 3 while having the same start and end point.

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Ameer Hamza
Ameer Hamza 2020-10-25
编辑：Ameer Hamza 2020-10-25

0 个投票

Try this interp1() based solution.
M = rand(8314, 3);
M_new = interp1(linspace(0,1,size(M,1)), M, linspace(0,1,144));

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David Hill
David Hill 2020-10-25

0 个投票

Not sure how you want to select the elements between the first and last.
newMatrix=reshape([yourMatrix(1:58:end),yourMatrix(end)],[144],[]);

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