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Recursive Function with two Base Cases

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MiauMiau
MiauMiau 2013-2-19
Hi
Let the Lucas Numbers be defined as follows:
1 for n = 1
3 for n = 2
L_n = L_(n-1) + L_(n-2) for n >= 3
Why doesn't my code work? Here is the code:
function a = lucas(N)
N = input('please enter an integer:')
if N == 1
a = 1;
elseif N == 2
a = 3;
elseif
a = lucas(N-1)+ lucas(N-2)
end
disp(N)
end
thanks!

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回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-2-19
编辑：Azzi Abdelmalek 2013-2-19
It's not elseif use else
Also you are using a function with input argument N, why in your function you added:
N = input('please enter an integer:')
What you should do is:
function a = lucas(N)
if N == 1
a = 1;
elseif N == 2
a = 3;
else
a = lucas(N-1)+ lucas(N-2)
end
disp(N)
And in windows command
N = input('please enter an integer:')
a=lucas(N)
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Azzi Abdelmalek
Azzi Abdelmalek 2013-2-19
编辑：Azzi Abdelmalek 2013-2-19
I forget to remove , input from your function. It gives 7 for N=4
save this function
function a = lucas(N)
if N == 1
a = 1;
elseif N == 2
a = 3;
else
a = lucas(N-1)+ lucas(N-2)
end
disp(N)
in windows command type
lucas(4)

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