Loop an if with different parameters

Question

Brilliant Purnawan 2020-11-15

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/648613-loop-an-if-with-different-parameters

回答： Setsuna Yuuki. 2020-11-15

Hi, doing some practice codings and ran into a snag. So, i'm trying to plot(t,y) with different matrix 'e' values? Let's say my first 'e' would be [-1; -2; -3; -4], and second [-2; -3; -4; -5] and keeps increasing with increments of 1 until a maximum value of [-7; -8; -9; -10], and plot everything in the same graph? How would I go about this? Code is below

e = [-1; -2; -3; -4]
    
K = place(A,B,e);
tspan = 0:0.01:200;
if(c==-1)
    y0=[0; 0; 0; 0];
    [t,y] = ode45(@(t,y)Equation(y,m,M,l,g,b,-K*(y-[4; 0; 0; 0])),tspan,y0);
elseif(c==1) 
    y0=[-3; 0; pi+.1; 0];
    [t,y] = ode45(@(t,y)Equation(y,m,M,l,g,b,-K*(y-[1; 0; pi; 0])),tspan,y0);
else
end
plot(t,y);

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Answer 1

Setsuna Yuuki. 2020-11-15

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/648613-loop-an-if-with-different-parameters#answer_545243

在 MATLAB Online 中打开

You can use for to graph more than once.

for n=1:7
    
    e = -n:-1:-n-3 % e values [-1 -2 -3 -4]
    e = e'; %[-1;-2;-3;-4]
    %Your code....
    if(c==-1)
        y0=[0; 0; 0; 0];
        [t,y] = ode45(@(t,y)Equation(y,m,M,l,g,b,-K*(y-[4; 0; 0; 0])),tspan,y0);
    elseif(c==1) 
        y0=[-3; 0; pi+.1; 0];
        [t,y] = ode45(@(t,y)Equation(y,m,M,l,g,b,-K*(y-[1; 0; pi; 0])),tspan,y0);
    else
    end
    % Your code end
    
    plot(t,y); hold on;
end