Index exceeds matrix dimensions but only in parfor and not for

5 次查看（过去 30 天）
Naty S
Naty S 2013-2-25
编辑： Thomas Dolivo 2018-4-12
hey I am new to parallel computing. I have been trying to get my simulation run using parfor, however when i am using parfor i am getting the following error:
I have got this weird error which i don't know how to handle. I don't get any error when using for instead of parfor. any idea? Thanks! Naty
Error using parallel_function (line 598)
Index exceeds matrix dimensions.
Error stack:
run_ode.m at 62
run_sim.m at 9
  5 个评论
显示 3更早的评论
Naty S
Naty S 2013-2-26
编辑：Naty S 2013-2-27
amm... The weird thing is that it's all working when i am using plain "for" loops . only when I am using parfor it claims that there is an error in the function. The error occurs at the line with xout, just before the last line.
background: It's solves ODE with event's functions. so it has finished solving a previous ODE and now finished solving another ODE ,the problem with the "for" loop combining the two vectors into a longer vector, the "stance to flight" is required to switch from polar to Cartesian axis. Thanks!
options=odeset('Events', @liftoff_event, 'AbsTol', 1e-14, 'MaxStep', 0.01, 'Refine', 3);
[t,x,te,ye,ie]=ode45(@stance_dynamics,[tstart,t_f],x0,options);
nt=length(t);
tout=[tout;t(2:nt)];
for it1 = 2 : nt %Changing for Polar to Cartisen Cord.
tmp_x = stance_to_flight(x(it1, :));
xout = [xout; tmp_x(1:4), x(it1, 1:2)];
end
Matthew Phillips
Matthew Phillips 2013-10-3
编辑：Matthew Phillips 2013-10-3
I'm having this exact same problem. Pretty hard to debug given that you can't put breakpoints within a parfor loop.
Running
>> dbstop if error
halts on this block in parallel_function.m, line 579ff:
try
R = distributed_execution(...
P, base, limit, W, k, NN, NN0, consume, supply, ...
reduce, R, concatenator, ...
consume_supply_reduce_concat, ...
consume_bit, supply_bit, reduce_bit, concat_bit);
break;
catch err
...
[err, possibleSourceFiles] = iMaybeTransformMissingSourceException(err, F);
if isempty(possibleSourceFiles) || ~attachFilesAndRetryOnError
throwAsCaller(err);
end
possibleSourceFiles is empty. parallel_function.m is called directly from the file containing my parfor loop so it is not possible for me to track down its inputs (in particular, the function handle 'consume') and the possible source of this error.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（3 个）

F Poelwijk
F Poelwijk 2014-5-1
One common reason for this error to occur is when you try to insert entries to an array that is not pre-defined outside the parfor loop. A for loop has no problems with this (though the editor will suggest pre-allocation for speed), but a parfor loop does. Try pre-defining the variable, e.g. x = zeros(n,m).
  2 个评论
Matt J
Matt J 2014-5-2
编辑：Matt J 2014-5-3
Not sure why parfor would care about pre-allocation more than for. In the following test script, I also get no errors
parfor i=1:10000
x(i)=i;
end
Neill Weiss
Neill Weiss 2014-5-28
This worked for me. I needed to preallocate an array of objects. Thanks F Poelwijk.

请先登录，再进行评论。

Khalid
Khalid 2016-4-17
Hi, I ran into the same problem with some code, and thought I'd explain the issue and fix in case someone else gets the same error for the same reason. Below is a minimal reproducible example of the problem. You will see the for and parfor loops below are identical. The for loop runs ok, but the parfor loop faults.
This is likely to come up if you have different running options and some variables are set in some of them but not in others. It appears the parfor error checking is thrown, it is probably checking that all possible execution paths through the parfor loop are acceptable, whereas in the example below they are not. Note that if you set doAssignment to true below both types of loop will run. The fix in my case is to do per-allocation for all possible running options through the parfor loop.
- Khalid.
doAssignment = false;
if doAssignment
a = zeros(2,1);
end
for i = 1:2
if ~doAssignment
disp('run here');
else
disp('dont run here');
disp(a(i)); %#ok<*SAGROW,*UNRCH>
end
end
parfor i = 1:2
if ~doAssignment
disp('run here');
else
disp('dont run here');
disp(a(i));
end
end
  1 个评论
Thomas Dolivo
Thomas Dolivo 2018-4-12
编辑：Thomas Dolivo 2018-4-12
Thank you very much for your comment. I had a similar situation that I identified thanks to your hint.
foo = zeros(4,1);
parfor i = 1:8
if i <= 4
bar = foo(i); % this causes an error in parfor, but not in for
else
bar = foo(i-4);
end
end
By unifying the access to the array, the error was fixed:
foo = zeros(4,1);
parfor i = 1:8
if i <= 4
j = i;
else
j = i-4;
end
bar = foo(j);
end
@Mathworks: The error message should be more clear. Why can’t it at least give a line number of where the “Index exceeds matrix dimensions” occured?

请先登录，再进行评论。

Matt J
Matt J 2013-10-3
编辑：Matt J 2013-10-3
There's too little information about the code being run to say much. My guess is that the loop iterations might not really be order-independent for some subtle reason. For example, maybe some of the functions you are calling within the parfor loop contain persistent or global variables -- something which is supposed to remember the outcome of previous iterations in a for loop. That would be illegal in a parfor, of course, since the sequence of iterations can't be predicted.
  1 个评论
Matt J
Matt J 2013-10-3
One way to test this would be to replace the parfor loop with a normal for loop, but run the iterations in a crazy random order
for i=randperm(1:Nsteps)
...
end
and see if the result is affected.

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by