Displaying a linked list as an array?
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How would I display a linked list as an array of the values of every node in the list, in the order of which the list traverses? Ok, so let's say I have list structure with list.root as the index of the first node in the list. Each node has a value and a next pointer, indicating the index of the next node in the list. How would I show every value within the list structure as a single array of values?
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Jan
2013-3-4
There is a nearly infinite number of methods you could implement a linked list in Matlab. So how could we know the structure of your data? Please add any details by editing the question - not as answer or comment.
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Walter Roberson
2013-3-6
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Start an array with []. Start at list.root . Repeat {If the current list point is not the end of list, add list.value to the end of the array, and make list.next the current list point.}
3 个评论
Joe
2013-3-8
Walter Roberson
2013-3-8
end-of-list marker rather than the last node, because you need to include the information from the last node.
Joe
2013-3-8
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