or() in categorical variable

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TAEKYU EOM
TAEKYU EOM 2020-11-23
评论： TAEKYU EOM 2020-11-23
I don't know why the results of index1 and index2 are different.
The variable
financial_status=[1,2,3,4,5];
index1 = find(financial_status==or(1,2));
index2 = find(financial_status>=1&financial_status<=2);

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采纳的回答

dpb
dpb 2020-11-23
Because
>> or(1,2)
ans =
logical
1
>>
You're apparently looking for
>> ismember(financial_status,[1,2])
ans =
1×5 logical array
1 1 0 0 0
>>
Rarely are the actual indices returned by find needed, but can be if this is one of those cases that simply using the logical addressing array isn't sufficient.

更多回答（1 个）

Walter Roberson
Walter Roberson 2020-11-23
编辑：Walter Roberson 2020-11-23
ismember(financial_status, 1:2)
At the moment I cannot think of any computer language that expresses a set membership test in terms of an equality test. Which computer language were you inspired by?

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