Problem with IF statement

why doesn't it give me a result if I enter " if D == l " I wan't to calculate all initial velocities and angles at which the length is 100m.
clear all
close all
clc
%1
v0 = [15:0.001:60]; %initial velocity
kot = [15:60]; %angle
g = 9.81; %gravity
l = 100; %distance
for i = 1:length(v0)
for j = 1:length(kot)
D = (v0(i)^2*sind(2*kot(j)))/g; %distance
if D == l
fprintf('Vo = %.2f m/s | kot = %.2f° | D = %.2f \n',v0(i),kot(j), D);
end
end
end

回答(1 个)

Rik
Rik 2020-11-27

0 个投票

Don't use clear all. You don't need it.
I suspect you encountered the wondrous world of floats. Computers don't have infinite memory and may round numbers in ways that you don't expect. This is especially a problem if you are asking for exact equality, while you would be satisfied with equality within machine precision.
Instead of a==b use abs(a-b)<tol. You can use the eps function, or set another value.

4 个评论

This don’t help but thanks anyway.
Why not? Using the code below you can find how close D gets to 100. So if you pick a tolerance that is above that, your code will print.
v0 = 15:0.001:60; %initial velocity
kot = 15:60; %angle
g = 9.81; %gravity
l = 100; %distance
[i,j] = meshgrid(1:length(v0),1:length(kot));
D = (v0(i).^2.*sind(2*kot(j)))/g; %distance
smallest_diff=min(abs(D(:)-100))
smallest_diff = 4.0932e-05
%repeat your code, but with the edits I described
tol=5e-5;
for i = 1:length(v0)
for j = 1:length(kot)
D = (v0(i)^2*sind(2*kot(j)))/g; %distance
if abs(D-l)<tol
fprintf('Vo = %.2f m/s | kot = %.2f° | D = %.2f \n',v0(i),kot(j), D);
end
end
end
Vo = 36.93 m/s | kot = 23.00° | D = 100.00
sorry my bad. thanks for answer
No problem. If my answer solved your question, please consider marking my answer as accepted answer. If not, feel free to comment with your remaining issues.

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2020-11-27

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Rik
2020-11-27

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