I have two 3d points, A(1,0,0) and B(0,1,0). And I connect these two points as a line AB. How to divide this line into 10 equally segments and get their coordinates?

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Alan
Alan 2020-11-28
编辑： Jan 2020-11-30
Hello,
I have two 3d points, A(1,0,0) and B(0,1,0). And I connect these two points as a line AB. How to divide this line into 10 equally segments and get their coordinates?
Many thanks!

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采纳的回答

Ameer Hamza
Ameer Hamza 2020-11-28
编辑：Ameer Hamza 2020-11-28
This is one way
A = [1,0,0];
B = [0,1,0];
n = 10;
X = [A; B];
t = linspace(0, 1, n+1);
points = interp1([0 1], X, t)
Result
>> points
points =
1.0000 0 0
0.9000 0.1000 0
0.8000 0.2000 0
0.7000 0.3000 0
0.6000 0.4000 0
0.5000 0.5000 0
0.4000 0.6000 0
0.3000 0.7000 0
0.2000 0.8000 0
0.1000 0.9000 0
0 1.0000 0

更多回答（2 个）

M.Many
M.Many 2020-11-28
Hi, you can use vectors to solve this problem
AB = [-1 1 0]' %vector AB
discretization = linspace(0,1,10) %10 values
vectors = AB*discretization %matrix multiplication
This gives the matrix whose columns are the vectors AP, to get the coords of the points P just add the coords of A to the columns of 'vectors'
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M.Many
M.Many 2020-11-28
Yes, you can do this if you add these lines at the end of the code
AB = [-1 1 0]' %vector AB
discretization = linspace(0,1,11) %11 values for 10 segments
vectors = AB*discretization %matrix multiplication
A = [1,0,0]'
P = A+vectors
The result is
P =
1.0000 0.9000 0.8000 0.7000 0.6000 0.5000 0.4000 0.3000 0.2000 0.1000 0
0 0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000 1.0000
0 0 0 0 0 0 0 0 0 0 0
Where each culumn is the coordinates of corresponding point P

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Jan
Jan 2020-11-28
编辑：Jan 2020-11-30
A = [1, 0, 0];
B = [0, 1, 0];
ab = B - A;
v = linspace(0, 1, 10).';
C = A + v .* ab % >= R2016b, auto-expanding
% For older versions:
C = A + bsxfun(@times, v, ab)

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