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How to sort numbers in a char

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arthur doroshev
arthur doroshev 2020-11-30
评论： arthur doroshev 2020-11-30
Hello,
I have a difficulty to make a sorting in a char. I need to sort the next char by the second number of each big Letter, for example:
G([1.1277],u1+[2.9793],[0.3143])+G([0.2594],u1+[3.8532],[0.31232])+Y([4.1689],u1+[9.0615],[0.024204])+D([1.2424],u1+[1.5934],[0.024204])
it should be like that as a result:
Y([4.1689],u1+[9.0615],[0.024204])+G([0.2594],u1+[3.8532],[0.31232])+G([1.1277],u1+[2.9793],[0.3143])+D([1.2424],u1+[1.5934],[0.024204])
If someone could help me with that, it will be very helpful
Thank a lot :)
  1 个评论
Rik
Rik 2020-11-30
You need to solve difficult problems step by step.
  1. Split the char into the terms
  2. Extract the relevant number from each term
  3. Use the second output of sort to determine the order
  4. Apply the sort to the tems
  5. Stich the terms back together

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采纳的回答

Stephen23
Stephen23 2020-11-30
Ran in:
str = 'Y([4.1689],u1+[9.0615],[0.024204])+G([0.2594],u1+[3.8532],[0.31232])+G([1.1277],u1+[2.9793],[0.3143])+D([1.2424],u1+[1.5934],[0.024204])';
spl = regexp(str,'[A-Z]\([^\)]+\)','match');
vec = sscanf(str,'%*[A-Z]([%*f],u1+[%f],[%*f])+');
[~,idx] = sort(vec,'descend');
out = join(spl(idx),'+');
out = out{1}
out = 'Y([4.1689],u1+[9.0615],[0.024204])+G([0.2594],u1+[3.8532],[0.31232])+G([1.1277],u1+[2.9793],[0.3143])+D([1.2424],u1+[1.5934],[0.024204])'

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