traversing an array of elements

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Raman 2013-3-13

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/66976-traversing-an-array-of-elements

i've the following list of elements as

 block 2=10
 block 5=16
 block 1= 16
 block 7=16
 block 4= 23
 block 6=31
 block 3= 31

i.e i've a total of 7 block numbers

the list is in sorted order...

i want to traverse it and find a match between block values like 'block 5', 'block 1' and 'block 7' match

'block 6' and 'block 3' match.. and print these blocks with matching values

how this can be done?

traversing a single list of array of following type i know like

    function traverse
  clc;
  a=[ 1 2 2 3 3 4 4 4 4]
  len=length(a)-1;
  for i=1:len
      if(a(i)==a(i+1))
          fprintf('\n%d and %d\n',a(i),a(i+1));
      end
  end

but to deal with the above list i dont know help me in doing so....

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Walter Roberson 2013-3-13

What is the name of your array that is of the form "[s,blockNumber]" ? Are the values in it stored by columns, so Array(2,1) is the second "s" value?

Raman 2013-3-14

在 MATLAB Online 中打开

i've an array of the form

a=[blockNumber(:), S(:)].'

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采纳的回答

Jan 2013-3-14

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/66976-traversing-an-array-of-elements#answer_78591

编辑：Jan 2013-3-14

在 MATLAB Online 中打开

A simple approach:

S = [2, 10;  5, 16;  1, 16;  7, 16;  4, 23;  6, 31;  3, 31];
v = unique(S(:, 2));
for iv = 1:length(v)
  matchIndex = (S(:, 2) == v(iv));
  matchBlock = S(matchIndex, 1)
  fprintf('%d:', v(iv));
  fprintf(' %d', matchBlock);
  fprintf('\n');
end