traversing an array of elements

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Raman
Raman 2013-3-13
i've the following list of elements as
block 2=10
block 5=16
block 1= 16
block 7=16
block 4= 23
block 6=31
block 3= 31
i.e i've a total of 7 block numbers
the list is in sorted order...
i want to traverse it and find a match between block values like 'block 5', 'block 1' and 'block 7' match
'block 6' and 'block 3' match.. and print these blocks with matching values
how this can be done?
traversing a single list of array of following type i know like
function traverse
clc;
a=[ 1 2 2 3 3 4 4 4 4]
len=length(a)-1;
for i=1:len
if(a(i)==a(i+1))
fprintf('\n%d and %d\n',a(i),a(i+1));
end
end
but to deal with the above list i dont know help me in doing so....
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Walter Roberson
Walter Roberson 2013-3-13
What is the name of your array that is of the form "[s,blockNumber]" ? Are the values in it stored by columns, so Array(2,1) is the second "s" value?
Raman
Raman 2013-3-14
i've an array of the form
a=[blockNumber(:), S(:)].'

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Jan
Jan 2013-3-14
编辑：Jan 2013-3-14
A simple approach:
S = [2, 10; 5, 16; 1, 16; 7, 16; 4, 23; 6, 31; 3, 31];
v = unique(S(:, 2));
for iv = 1:length(v)
matchIndex = (S(:, 2) == v(iv));
matchBlock = S(matchIndex, 1)
fprintf('%d:', v(iv));
fprintf(' %d', matchBlock);
fprintf('\n');
end
For larger data sets, histc would be much faster. Search for this command in this forum to find more examples.
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Raman
Raman 2013-3-19
sir i have corrected it....
Jan
Jan 2013-3-19
@Jassy: Where did you post the complete error message?

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