Assign multi-dimension array to data structure array without for-loop

Question

0 个投票

I want to remove for-loop in order to assign array to data structure array.

 S(1:3) = struct('a', zeros(3,3));
 tmp = random('Normal', 0, 1, 3, 3, 3);
 for ie = 1:3
   S(ie).a = tmp(:,:,ie);
 end

Here, I want to obtain S(:).a without for-loop. In addition, S(:).a is updated sometimes.

Many Thanks!

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Jan 2011-5-4

The FOR loop is fine and efficient. Why do you want to remove it?

Answer 1

Matt Fig 2011-5-4

0 个投票

For example:

clear T S
T = rand(3,3,3);
S(1:3) = struct('a', mat2cell(T,3,3,[1 1 1]));
isequal(T(:,:,2),S(2).a) % just to check...

Answer 2

Daehung Kang 2011-5-4

0 个投票

If I have other fields in S(:), it should have following error. dissimilar structure.

Also, I want to update S(:).a sometimes, not declaration of structure field.

Thanks again.

Oleg Komarov 2011-5-4

The you can't do it w/o a loop.

Matt Fig 2011-5-4

These are details you left out of your original question, and they change the outcome. I did, however, answer your original question...