Got some problems when trying to plot with a shifting angle in 2D Plotting ?

Question

Haytham Mohamed 2013-3-16

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/67441-got-some-problems-when-trying-to-plot-with-a-shifting-angle-in-2d-plotting

采纳的回答： Jan

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when i try to plot from (0,0) it becomes great as the below Pic :

The Codes Are :-

hold on;grid;
ang=30;
theta=0;
for i=0:(360/ang)
xl=[0 15*cos(theta*pi/180)];
yl=[0 15*sin(theta*pi/180)];
plot(xl,yl,'-r')
theta=(i+1)*ang;
end

But when i try to change the Co-ordinates it becomes like this :-

The Codes As Below :-

hold on;grid;
ang=30;
theta=0;
for i=0:(360/ang)
xl=[5 20*cos(theta*pi/180)];
yl=[5 20*sin(theta*pi/180)];
plot(xl,yl,'-r')
theta=(i+1)*ang;
end

Thanks & Sorry for long words :D

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Jan 2013-3-16

You show us the code and the output, but do not explain, what the actual problem is. Do you expect the graphics to be symmetrical?

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Answer 1

Jan 2013-3-16

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/67441-got-some-problems-when-trying-to-plot-with-a-shifting-angle-in-2d-plotting#answer_78907

编辑：Jan 2013-3-16

在 MATLAB Online 中打开

The posted code moves the start points from (0,0) to (5,5) and the end points of each line are located on the circle around (0,0) with radius 20. I guess that you want a circle around (5,5) with radius 15:

hold on;grid;
ang=30;
theta=0;
for i=0:(360/ang)
  xl = [5, 5 + 15*cos(theta*pi/180)];
  yl = [5, 5 + 15*sin(theta*pi/180)];
  plot(xl,yl,'-r')
  theta = (i+1)*ang;
end