Got some problems when trying to plot with a shifting angle in 2D Plotting ?
显示 更早的评论
when i try to plot from (0,0) it becomes great as the below Pic :
The Codes Are :-
hold on;grid;
ang=30;
theta=0;
for i=0:(360/ang)
xl=[0 15*cos(theta*pi/180)];
yl=[0 15*sin(theta*pi/180)];
plot(xl,yl,'-r')
theta=(i+1)*ang;
end
But when i try to change the Co-ordinates it becomes like this :-
The Codes As Below :-
hold on;grid;
ang=30;
theta=0;
for i=0:(360/ang)
xl=[5 20*cos(theta*pi/180)];
yl=[5 20*sin(theta*pi/180)];
plot(xl,yl,'-r')
theta=(i+1)*ang;
end
Thanks & Sorry for long words :D
1 个评论
Jan
2013-3-16
You show us the code and the output, but do not explain, what the actual problem is. Do you expect the graphics to be symmetrical?
采纳的回答
The posted code moves the start points from (0,0) to (5,5) and the end points of each line are located on the circle around (0,0) with radius 20. I guess that you want a circle around (5,5) with radius 15:
hold on;grid;
ang=30;
theta=0;
for i=0:(360/ang)
xl = [5, 5 + 15*cos(theta*pi/180)];
yl = [5, 5 + 15*sin(theta*pi/180)];
plot(xl,yl,'-r')
theta = (i+1)*ang;
end
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2013-3-16
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