How do I use regexprep to replace final NaN values in a matrix?

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Derek
Derek 2013-3-20
I have a numeric data stream like this:
NaN NaN NaN 100 102 101 99 102 NaN NaN NaN NaN NaN 101 103 NaN NaN, etc
I'd like to replace the last NaN in each string of NaNs with a zero so it would look like this:
NaN NaN 0 100 102 101 99 102 NaN NaN NaN NaN 0 101 103 NaN NaN
Is this a good regexprep situation or should I do find()?

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回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-3-20
A=[NaN NaN NaN 100 102 101 99 102 NaN NaN NaN NaN NaN 101 103 NaN NaN]
A(diff(isnan([A 0]))==-1)=0
Jan
Jan 2013-3-21
A = [NaN NaN NaN 100 102 101 99 102 NaN NaN NaN NaN NaN 101 103 NaN NaN];
A(strfind(isnan(A), [true, false]) = 0;

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