binary process, biner to decimal

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Internazionale
Internazionale 2013-3-21
i have binary number 20 bit (uint8), i want to convert the binary number to decimal. i use bin2dec but before i must convert num2str so i can use bin2dec. 20 bit (1x20) --> num2str --> 1x58 char. when i start to dec2bin, matlab error because binary string must be 52 bits or less. how to overcome this problem ?
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Jan
Jan 2013-3-21
The text description of the input is in general less exact as a shart Matlab example. What exactly is "a binary number 20 bit (uint8)? Is this a [1 x 20] uint8 vector, or a [1 x 3] uint8 vector with 4 unused bits?

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Walter Roberson
Walter Roberson 2013-3-21
b = uint8([1 1 0 0 1 1 0 1 0 1 1 1 0 0 1 1 0 1 0 1]);
bin2dec( char(b + '0') )
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Internazionale
Internazionale 2013-3-21
it works, can you describe to me how it works ? especially when bin2dec (char(b+'0')), thanks
Walter Roberson
Walter Roberson 2013-3-22
'0' is the character representation of zero. add 0 (the number) to it and you will have a value that is still the value for the character representation of '0'. Use char() to turn the value back into the character. So char(0 + '0') is going to be '0'.
Now, the character representation of '1' has a value that is exactly 1 greater than the value for the character representation '0'. ('1' - '0') is 1. So char(1 + '0') = '1'.
Therefore to turn 0 or 1 into '0' or '1', add '0' to the value and take char() of the result.

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Jan
Jan 2013-3-21
编辑：Jan 2013-3-21
Guessing that your input is e.g.:
b = uint8([1 1 0 0 1 1 0 1 0 1 1 1 0 0 1 1 0 1 0 1]);
Then assuming, that the 1st element is the most significant bit:
d = 2 .^ (length(b)-1:-1:0) * double(b(:));
This is the dot-product of an [1xN] and [Nx1] vector, such that the sum is calculated implicitly.

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