how to creating matrix h 4x2 with some rules

2 次查看(过去 30 天)
I have some trouble when creating matrix 4x2 with rules like below. the first column are integer and the other column are random number. I already create the syntax below.
for ii = 1:8,
nilai = mod(ii,2);
if nilai == 0
x(ii) = 0.95 + (1.05-0.95)*x(ii);
elseif nilai ~= 0
x(ii) = round(3 + (30-3)*x(ii));
elseif nilai ~= 0
x(ii) = 0.01 + (0.055-0.01)*x(ii);
else
x(ii) = 1.0 + (1.15-1.0)*x(ii);
end
end
x = reshape(x,4,2)';
but the result are
??? Error using ==> reshape
To RESHAPE the number of elements must not change.
anyone can help me with this problem..? any solutions are very welcome..
thank you.

采纳的回答

the cyclist
the cyclist 2013-3-21
What is the shape of x before you start? It seems that it is probably not an 8-element array, so the reshape fails.
  3 个评论
the cyclist
the cyclist 2013-3-21
You did not answer my question. What is the shape of x BEFORE this loop?
As you can see from Image Analyst's answer, there is no problem if x is 1x8 before your loop.
Noru
Noru 2013-3-27
i think i ask the wrong question..
thanks for your help.. :))

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更多回答(1 个)

Image Analyst
Image Analyst 2013-3-21
I got a different error message due to x not being predefined and your new x(ii) depends on your old x(ii). When I predefined x, it ran with no errors:
x = zeros(1, 8);
for ii = 1:8
nilai = mod(ii,2);
if nilai == 0
x(ii) = 0.95 + (1.05-0.95)*x(ii);
elseif nilai ~= 0
x(ii) = round(3 + (30-3)*x(ii));
elseif nilai ~= 0
x(ii) = 0.01 + (0.055-0.01)*x(ii);
else
x(ii) = 1.0 + (1.15-1.0)*x(ii);
end
end
x = reshape(x,4,2)'
In the command window:
x =
3 0.95 3 0.95
3 0.95 3 0.95
  2 个评论
Noru
Noru 2013-3-21
now i already done create a matrix like you do, but i want to make the value of the 3rd column like 2nd and 4th(non integer number) like below
x =
8 0.67 0.32 0.76
14 0.49 0.21 0.53
do you have any solution..?
Image Analyst
Image Analyst 2013-3-21
% make the value of the 3rd column like 2nd
x(:,3) = x(:,2);
% make the value of the 3rd column like 4th
x(:,3) = x(:,4);

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