How to open a .wav file from matlab using a string name?

Question

MatlabFan 2013-3-31

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/69265-how-to-open-a-wav-file-from-matlab-using-a-string-name

Hi,

... and thanks for helping.

I want to open a .wav file in matlab just from a string name. I don't know what the string name will be until I run the program. I do know that whatever the string name will be, it will exist in the current folder.I have tried multiple approaches unsuccessfully. below is the latest that I have produced

 if true
     list=get(handles.targetSelection_popupmenu,'String');
 val=get(handles.targetSelection_popupmenu,'Value');
 str=list{val};
 filename=[sr,'.wav'];
 [VoiceTrgt fsTrgt]=wavread(filename,'.wav');
   end

It does not work. so, as you can guess, str can be, say, Symphony11 or Symphony12 or whatever... I want to read the Symphony.

Thanks.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Wayne King 2013-3-31

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/69265-how-to-open-a-wav-file-from-matlab-using-a-string-name#answer_80517

编辑：Wayne King 2013-3-31

在 MATLAB Online 中打开

Can you say what error you are getting? I'm not sure why you have the following

 filename=[sr,'.wav'];
 [VoiceTrgt fsTrgt]=wavread(filename,'.wav');

Why are you calling wavread with an '.wav' input argument? There is no such input argument. The above is probably giving you an "unrecognized data format" error because it expects a string like 'double' or 'native'

Just do the following

 filename = [sr, '.wav'];
 [VoiceTrgt fsTrgt]=wavread(filename);

Assuming that filename ends up as something like symphony11.wav.

By the way, the recommend functionality to use is audioread() assuming you have a version of MATLAB that contains that function.

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

MatlabFan 2013-3-31

First of all Wayne, Thank you for assisting me. I realized that I had two mistakes in my code: instead of sr it should have been str (see code above. Also, as you pointed out, I should not have called the wavread with a '.wav' input argument the way I did it in the code above. Thanks.

请先登录，再进行评论。