how do Create a message signal m(t) = cos(2πfmt), fm = 5 KHz. and Plot the signal both in time domain and the magnitude of its spectrum in frequency domain?

12 次查看(过去 30 天)
how do Create a message signal m(t) = cos(2πfmt), fm = 5 KHz. and Plot the signal both in time domain and the magnitude of its spectrum in frequency domain?
My code is below for time domain
>> fm = 5000;
>> t = 0: 0.01: 10;
>> y = cos(2*pi*fm*t)
>> plot(t,y)
I just get a straight line???

回答(5 个)

Rick Rosson
Rick Rosson 2013-3-31
编辑:Rick Rosson 2013-3-31
The sampling rate that you are using is 100 samples per second, whereas the carrier frequency of the message signal is 5,000 hertz. According to the Nyquist Sampling Theorem, you need a sampling rate that is at leat twice the highest frequency that you want to represent. So, in this example, you need a sampling rate of at least 10,000 samples per second.
Let's try 800,000 samples per second, and see if it helps:
Fs = 800e3;
dt = 1/Fs;
t = (0:dt:0.002-dt)';
Fm = 5000;
y = cos(2*pi*Fm*t);
figure;
plot(t,y);
  2 个评论
Ankit Ghosh
Ankit Ghosh 2017-8-20
编辑:Ankit Ghosh 2017-8-20
fs = 1e3;
dt = 1/fs;
t = (0:0.001:10)';
fm = 2e3;
sig = sin(2*pi*fm/fs*t);
plot(t,sig);
title('sin wave with 1KHz sampling rate')
This is working perfectly fine for me as per the text book equations.

请先登录,再进行评论。


RISET
RISET 2017-1-15
编辑:RISET 2017-1-15
as fm =5000 ; so (fm*t)=an integer; for cos(2*pi*n) value is always=0; so try to change it to some other values like 4999 or 3479 or 23 or 5 ;yes for fm = 5947; t = 0: 0.01:1; y = cos(2*pi*fm*t); plot(t,y) u will see the graphs cosine nature is lost it is due to the t intervals u have taken .try to change them as small as possible ....like fm = 5947; t = 0: 0.001:.1; y = cos(2*pi*fm*t); plot(t,y) u will see what u want....{i have not maintained the desired frequency but try to conceptualise what nyquist rate leading towards)...

Jayram Naykinde
Jayram Naykinde 2021-10-25
perform Sampling of a signal
clc;
clear all;
close all;
f0=3;
fs=10;
T=1/f0;
t=0:0.001:5*T;
x_t=cos(2*pi*3*t);
Ts=1/fs;
n=0:Ts:5*T;
x_n=cos(2*pi*f0*n);
subplot(2,1,1)
plot(t,x_t,'-.');
xlabel('Time')
ylabel("x(t)")
subplot(2,1,2) stem(n,x_n,"filled"); xlabel('Time') ylabel("x(n)")

azad Thanveer
azad Thanveer 2022-6-2
>> fm = 5000; >> t = 0: 0.01: 10; >> y = cos(2*pi*fm*t) >> plot(t,y)

azad Thanveer
azad Thanveer 2022-6-2
fm = 5000;
>> t = 0: 0.01: 10;
>> y = cos(2*pi*fm*t)
>> plot(t,y)

类别

Help CenterFile Exchange 中查找有关 Spectral Measurements 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by