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how to shift an array value upward ?

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preet
preet 2013-4-2
a=[10,14,5,6,7,19]
in this array need to build an array a[] again but the value should not be less than or equal to 15 i need it
a=[24,18,19]
when i shift the value after adding my value which i have already added remain in the array like this
in 1st loop i have result lke this
a=[24,5,6,7,19,19]
how to get the right result with shifting
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preet
preet 2013-4-2
i m adding value with array itself if the current value of array is less or equal to 15.

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采纳的回答

Mahdi
Mahdi 2013-4-2
Just use
a=a(1:end-1)
to remove the last value.

更多回答（1 个）

Jan
Jan 2013-4-2
a = [10, 14, 5, 6, 7, 19];
r = zeros(size(a)); % Pre-allocate maximal length
ri = 0;
q = 0;
for k = 1:length(a)
q = q + a(k); % Accumulate values of "a"
if q >= 15 % Flush accumulated value:
ri = ri + 1;
r(ri) = q;
q = 0;
end
end
r = r(1:ri); % Crop unused values
  2 个评论
preet
preet 2013-4-2
simon i want to a[ ] array again not r [].
Jan
Jan 2013-4-2
编辑：Jan 2013-4-2
@kpreet: Is this a serious question? What about adding this line at the end:
a = r;
Or you can do it "inplace", but the modifications are such tiny (changing all "r" to "a" and "ri" to "ai"), that I'd actually assume, that you could solve this by your own:
a = [10, 14, 5, 6, 7, 19];
ai = 0;
q = 0;
for k = 1:length(a)
q = q + a(k); % Accumulate values of "a"
if q >= 15 % Flush accumulated value:
ai = ai + 1;
a(ai) = q;
q = 0;
end
end
a = a(1:ai); % Crop unused values
It would be a kind idea to explain, if at least the values of "r" match your expectations.

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