Clear function inside a parfor loop: Transparency violation error
显示 更早的评论
Dear community,
I tried to find some answers about the topic in this title, but I found only the problem concerns to set the variable as empty.
I don't clear a variable but a function, as shown in the example below. This produce a transparency violation error. Could someone help me? I need to clear the function in every loops.
Kind regard
Califfo
parfor i=1:N1
for j = 1:N2
clear myfunction
[outputs] = myfunction(inputs);
end
end
采纳的回答
Jan
2020-12-27
What is the purpose of clearing the function? Do you want to get rid of persistently stored variables? This could be done more efficiently, e.g. by:
function outputs = myfunction(inputs)
persistent a,b
if nargin == 0
a = [];
b = [];
return;
end
end
Now call myfunction() instead of clearing it. This avoid a time-consuming reloading of the function from the disk and the reparsing.
更多回答（1 个）
Gouri Chennuru
2020-12-27
0 个投票
Hi,
You can refer to this link
Hope this helps!
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Translated by 
