Which method to use, basic for loop or loop through values of a vector

Vector ind has indices I want to loop through, x has values.
ind = [1 3 5];
x = [10 20 30 40 50 60 70];
ind_len = size(ind,2)
Approach 1: When using a for loop, should I use the basic incremental for loop, where I access each element of x with index values from ind vector
for i = 1:ind_len
x(ind(i))
end
Approach 2: Don't use ind_len length variable and assign ind vector to for loop
for i = ind
x(i)
end
Which method is efficient ?

 采纳的回答

x = rand(1, 1e6);
y = zeros(size(x));
ind = randperm(numel(x));
tic
for loop = 1:10
for k = 1:numel(ind)
y(ind(k)) = x(ind(k));
end
end
toc
tic
for loop = 1:10
for k = ind
y(k) = x(k);
end
end
toc
% Elapsed time is 0.395765 seconds.
% Elapsed time is 0.739708 seconds.
The first approach can be handled more efficiently.

更多回答(1 个)

More simpler, without loop
x(ind)
More, How to measure the performance of the code, link
The 2nd approach (If I must have to choose one from above)

2 个评论

Thank you for your time, I agree with your answer in printing it as such. But I intend to do other operation other than printing.
I measured the time for each of the for loops, the first approach turned out to be faster.
Elapsed time for first approach is 0.001047 seconds.
Elapsed time for second approach is 0.001211 seconds.
Great one, once I run the code, as given in the question..
ind = [1 3 5];
x = [10 20 30 40 50 60 70];
ind_len = size(ind,2);
tic
for i = 1:ind_len
x(ind(i));
end
toc
tic
for i = ind
x(i);
end
toc
Elapsed time is 0.000021 seconds.
Elapsed time is 0.000016 seconds.

请先登录,再进行评论。

类别

帮助中心File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by