code with out using loops

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omar khasawneh
omar khasawneh 2020-12-25
评论： Jan 2020-12-27
how can I write a code segment that flips an N*M array up to down *Do not use loops or flip function
  2 个评论
James Tursa
James Tursa 2020-12-26
What have you done so far? What specific problems are you having with your code?

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采纳的回答

Image Analyst
Image Analyst 2020-12-25
What did your course tell you about indexing? Like
indexes = startingValue : stepValue : endingValue;
If you still need help, reply only after reading the link below:
How do I get help on homework questions on MATLAB Answers? - MATLAB Answers - MATLAB Central
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Image Analyst
Image Analyst 2020-12-26
Read my comment again - there is no accusation. Just a question as to explain how we can help you with this question that can be solved in one line of code. Since it's only one line of code, it's hard to help you without doing the whole thing for you. That's why I gave the hint I did. If I give any more than that, then it's completely done and there is nothing more for you to do. At least this way, I think you can change variable names and be able to say you did it yourself.
Jan
Jan 2020-12-27
@omar khasawneh: There is no accusation. Image Analyst gave you a useful hint.

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更多回答（1 个）

omar khasawneh
omar khasawneh 2020-12-26
okay , I got it ...
I solved like this A = [1 2 3 ; 4 5 6; 7 8 9];
A = A' % transpos
A = rot180(A) %rotation
  1 个评论
Image Analyst
Image Analyst 2020-12-26
OK, that works as long as you have written a special rot180() function. I'm not seeing it in base MATLAB. If I instead use imrotate() to do that part:
A = [1 2 3 ; 4 5 6; 7 8 9];
A = A' % transpos
% A = rot180(A2) %rotation
A = imrotate(A, 180)
I get
A =
1 4 7
2 5 8
3 6 9
A =
9 6 3
8 5 2
7 4 1
Which is not flipped up to down. It also flips left to right.
The solution most MATLABers would use is a single line of code using the hint I gave. So here is a little bit more:
A = A(startingValue : stepValue : endingValue, :);
That's it. One single line of code. See if you can supply the values.

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