How to append for each iteration?

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Maria Hart
Maria Hart 2021-1-18
评论： Maria Hart 2021-1-18
Dear all,
the situation is the following: I have a projectlength of 3 years with an assumed number of hours of 10. For each hour the yield is calculated with a certain function (which I simplify in this example with the number 2). As the projectlength and hournumber should stay variable, I would like to first calculate the yield in each hour of the year (helper(k)) and then append the solutions of each projectyear below each other. So the yield should look like this:
I got the following so far, however, it does not work.
hournum = 10;
projectlength = 3;
yield = [];
for p=1:projectlength
for k = 1:hournum
helper(k)=2;
end
yield(p) = [yield(p); {helper(k)}];
end
Error Message: Index exceeds the number of array elements (0).
  2 个评论
Jan
Jan 2021-1-18
Whenever you write "does not work", append the error message or a details description of the difference between your expectations and the obtained results.
Maria Hart
Maria Hart 2021-1-18
Ok, thank you. I have added the error message.

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采纳的回答

Jan
Jan 2021-1-18
编辑：Jan 2021-1-18
hournum = 10;
projectlength = 3;
yield = cell(1, projectlength); % Pre-allocate as cell
helper = zeros(1, hournum); % Pre-allocate as vector
for p = 1:projectlength
for k = 1:hournum
helper(k) = 2;
end
yield{p} = helper;
end
  3 个评论
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Maria Hart
Maria Hart 2021-1-18
编辑：Maria Hart 2021-1-18
Thank you for your answer. If you would like to have instead a simple vector with all numbers beneath each other and no cell (I would like to plot all data), what would I do?

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