infinite series with loop in MATLAB

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how can find F in matlab , where the initial value of z =1
and i is loop from
i=1:10
thanks so much for any help.need code of program if possible
  2 个评论
David Hill
David Hill 2021-1-22
It is unclear what z array is (from i=1:10) and how i changes in the equation. Should there be another summation on the outside changing i from 1:10?
hasan s
hasan s 2021-1-22
编辑:hasan s 2021-1-22
thank you for your reply
yes .to chang z
there must summation for i=1:10 ,with initial value to z=1
and another summation k=1:infinity .....for series

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采纳的回答

Walter Roberson
Walter Roberson 2021-1-22
syms z I k real
F = symsum((-z*I)^k/(k*factorial(k)), k, 1, inf)
F = 
However, examine the behavior when k = 0, the lower bound from the equation. The denominator is k*k! which would be 0 * 0! which would be 0*1 which would be 0. So we have a potential problem with singularities, and need to look at the limit. For non-zero z and i, (-z*i)^0 would be 1. Thus we are looking at 1/0 and that is infinite. As that is a term that is included in the actual sum (k = 0 to infinity) we must conclude that F is infinite except for the case where z or i are 0.
  12 个评论
Walter Roberson
Walter Roberson 2021-1-22
编辑:Walter Roberson 2021-1-22
format long g
z = [1, rand(1,9)];
syms k real
F = sym(0);
for i = 1 : 10
F = F + symsum((-z(i))^k/(k*factorial(k)), k, 1, inf);
end
F
F = 
result = double(F)
result =
-4.34857820351754

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