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call consecutive variables for loop

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Ana
Ana 2013-4-17
Hi,
I have variables in the workspace with the following names: A2010,A2011, A2012.....
Need to to the following for each variable:
AA2010=A2010';
t = AA2010>=2000;
z = [find([true,diff(t)~=0]) numel(AA2010)+1];
idx = [z(1:end-1);z(2:end)-1];
i1 = idx(:,t(idx(1,:)));
i2 = i1(:,(diff(i1) + 1) >= 1);
out = arrayfun(@(x)AA2010(i2(1,x):i2(2,x)),1:size(i2,2),'un',0);
L=length(out);
I'm trying to use:
for i=2010:2037
eval(['A' num2string(i) '=i'])
end
however no results came out...
Any suggestions?
Thanks

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回答（3 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-4-17
It's not num2string but num2str. Also it's not a good idea to use eval
Walter Roberson
Walter Roberson 2013-4-17
Jan
Jan 2013-4-17
To mention it the third time: Do not do this. Storing indices inside the names of variables is a really bad idea, as you see already. Using an array instead, or two arrays, where one contains the values and the other the idnices, would be much clearer and easier to handle.

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