Axes OuterPosition going nuts

Question

Sjouke Rinsma 2021-1-22

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https://ww2.mathworks.cn/matlabcentral/answers/724043-axes-outerposition-going-nuts

评论： Jan 2021-1-23

Okay, so I have an old GUIDE-created figure (with custom toolbar, which is the reason I still use it) containing 4 axes which I have sorted two-by-two. I have set the Figure and all Axes' units to normalized. The axes are displayed in the figure as shown below. When I request the Position or TightInset values I get the correct normalized values. However, when I request the OuterPosition for these axes I get some ridiculous values, see code below. When everything is set to normalized, why oh why am I getting these results. In fact; how should it even be possible that I get values outside the 0-1 range when all is set to normalized? Any ideas?

A(1:4).OuterPosition
ans =
 -110.8247  -54.7364  193.1601   92.5802
ans =
 -110.8247  -54.2364  193.1601   92.5802
ans =
 -111.3247  -54.7364  193.1601   92.5802
ans =
 -111.3247  -54.2364  193.1601   92.5802

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Answer 1

Jan 2021-1-22

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https://ww2.mathworks.cn/matlabcentral/answers/724043-axes-outerposition-going-nuts#answer_603853

编辑：Jan 2021-1-22

在 MATLAB Online 中打开

When do you get these output position values? Before a drawnow or afterwards?

Please check again, if you are really checking the objects you thinks you are checking:

A(1).Color = [1,0,0]
drawnow
A(1).OuterPosition
A(1).Position
A(1).Units

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Sjouke Rinsma 2021-1-22

Okay, so I am to exuse myself... I made a boo boo.

It apparently did not come to mind I was mistaken in expecting all normalized positional values to be between 0 and 1... scaling doet not imply limiting when considering variables that depend on each other.

I'm working in a several thousand lines of code in which the setting of the axes to 'normalized' was accidentally preceded by a setting of the axes position to a normalized value (e.g. [0 0.5 0.5 0.5]). Because I additionally use a function that automatically sorts the axes layout for a given figure, the position value was again set to the normalized value ([0 0.5 0.5 0.5]) resulting in the OuterPosition becoming as indicated before.