Crop part of an image

3 次查看（过去 30 天）

显示更早的评论

Hamed 2013-4-18

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/72536-crop-part-of-an-image

评论： Ahmed Fasih 2016-6-21

Hi there.

i've an image : (120 * 160 px)

I want to crop part of that image where number is.

Finally result must be : (22 * 39 px)

Thank you for your help.

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Jan 2013-4-18

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/72536-crop-part-of-an-image#answer_82647

编辑：Jan 2013-4-18

在 MATLAB Online 中打开

You did not explain the type of the image variable. It might be a gray-scale image of type UINT8. Row a 3D array of an RGB image the procedure must be modified.

[row, col] = find(img);
cropped    = img(min(col):max(col), min(row):max(row));

Note that the image might be transposed when it is displayed, so perhaps you have to swap row and col.

6 个评论
显示 4更早的评论隐藏 4更早的评论

Image Analyst 2013-4-19

Jan's code works for binary images. An alternate method would be to use regionprops() to get the bounding box, then use imcrop().

Ahmed Fasih 2016-6-21

在 MATLAB Online 中打开

Flipped row & col.

>> z = blkdiag(zeros(1,3),[1 2; 3 0], zeros(3,1))
z =
     0     0     0     0     0     0
     0     0     0     1     2     0
     0     0     0     3     0     0
     0     0     0     0     0     0
     0     0     0     0     0     0
     0     0     0     0     0     0
>> [row, col]=find(z)
row =
     2
     3
     2
col =
     4
     4
     5
>> z(min(row):max(row), min(col):max(col))
ans =
     1     2
     3     0