Please help me on this coding about nested loops

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snr matlb 2021-1-25

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https://ww2.mathworks.cn/matlabcentral/answers/726433-please-help-me-on-this-coding-about-nested-loops

编辑： snr matlb 2021-1-26

I have to give time delay all jobs in the dataset to make a separation. You can find the structure of the 'list' dataset at attachment.

cond1: represents particles (1-30), I have all particles in the Figure, but I show a part of it, it is too long to share.

cond2: represents hourzone (between 1-8), each hourzone have different number of jobs, but each particle has same number of jobs into the hourzone.

cond3: represents entry point of each job into the production line.

param1: entry time

param2: 1st time for check

param3: 2nd time for check

param4: 3rd time for check

param times are depended previous param. If any param2,3 or 4 is zero, it means that there is no passing line at that point for corresponding job.

list = % contains all data I need to check conflicts at oven line crossing point.
for p=1:30                  % this is for ensuring check all particles in particle swarm opt. separately.
    for h=1:8               % this is for ensuring check all jobs that are in the same hourzone.
        
        checkgroup = []; % preparation for control loop        
        for i=1:100         % this is for reaching each job in the 'list'.
            if list(i,'cond3') == 5 || list(i,'cond3') == 8
                checkgroup(row) = list(i,:); %checkgroup holds jobs have common crossing point, so has to be checked for conflict and given delay.
            end
        end
               
        checkgroup = sortrows(checkgroup, 6);
        
        while k <= size(checkgroup,1)-1
            l = k + 1;
            while l <= size(checkgroup,1)
                if abs(checkgroup(l,'param2') - checkgroup(k,'param2') >= 60)
                    %no delay
                else
                    %giving delay                    
                    checkgroup(l,'param2') = checkgroup(l,'param2') + delay;                  
                    checkgroup = sortrows(checkgroup, 6);                        
                    k=0;
                    break
                end
                l=l+1;
            end
            k=k+1;
        end                   
                      
        checkgroup = []; % preparation for new control loop
        for i=1:100
            if (%different conditions)
                checkgroup(row) = list(i,:); %checkgroup holds have common crossing point, so has to be checked for conflict and given delay.
            end
            while k <= size(checkgroup,1)-1
            l = k + 1;
            while l <= size(checkgroup,1)
                if abs(checkgroup(l,'param3') - checkgroup(k,'param3') >= 60)
                    %no delay
                else
                    %giving delay                    
                    checkgroup(l,'param3') = checkgroup(l,'param3') + delay;                  
                    checkgroup = sortrows(checkgroup, 6);                        
                    k=0;
                    break
                end
                l=l+1;
            end
            k=k+1;
        end 
        
        %% I have to use this control loop (for i=1:100) 5 more times to check all conflicts at each crossing point.
        %% If I use just first for i=1:100 loop I had to define 5 more checkgroup1,2...5 list to check each conflict group separately. 
        
     end
end

How to filter the grouped data to check conflicts among the corresponding jobs? Do I need to use nested loops (for look for particle, hourzone and jobs_id), that is what I am planing to do, or is there an efficient way to do it except my algorithm that I share with you in the question part?

**As you noticed, 3 "for loop" works mainly and 2 nested "for-loop" OR 2 "while loop" (I have not decided yet, "while" probably) will be employed to compare jobs time and controlling for giving delay. This reduces algorithm performance.

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Stephen23 2021-1-26

Your explanation is not clear.

You are trying to explain your attempt, rather than what you are actually trying to achieve:

https://en.wikipedia.org/wiki/XY_problem

https://xyproblem.info

As far as I understand it, you have several independent variables, and you want to process each unique combination of those variables. Is that correct? Perhaps you are trying to do something like this:

https://www.mathworks.com/help/matlab/ref/splitapply.html#bux1l61

snr matlb 2021-1-26

编辑：snr matlb 2021-1-26

I explain my attempt because I will try to solve it by myself, so I just need to simplfy the loops.

Acually, I have 3 variables these are list.param2, list.param3 and list.param4.

I have to control each variable with some condition for example, jobs that have cond3 = 5 or cond3=8 has to be separated in terms of param2. These jobs must be separated by 60 sec.

But, I have to do this for each particle that I have 30 different particles and 8 different hour zones.

That is to say; each particle has 8 hourzones, and each hourzone have different number of jobs and I have to control jobs that are in the same particle and same hourzone if they have conflict.

For example, I have to check jobs that have cond3=5 or cond3=8 for make separation about times shared at param2 column in the list. for instance, lets check while cond1 = 1 and cond2 = 3. The new filtered table must be like that;

as you see that I filtered jobs that have cond3=5 or cond3=8 but, I just filtered just for cond1=1 and cond2=3. I will check this new table, then I will change only cond2, I will check again. Then when cond2 reaches to 8, I will change cond3 and then cond2 starts over.

But, I have to do this for all cond1 that the last one is 30, and cond2 in the each cond1.

I mean that while I am holding cond1=1, I have to filter all cond3=5 or cond=8 for different cond2=1 to 8. Then, I will check each jobs till cond2 reaches 8. When I finished all check for cond3=5 or cond3=8, I will change cond3 for example cond3=1 or cond3=2. When I finished all, I will increase the cond1=2 then whole process will be repetaed, then I will do this till I finish them when cond1=30.

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