Beginner: Mex array size too large?

Question

mick strife 2013-4-19

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/72801-beginner-mex-array-size-too-large

Hello my friends,

i m a beginner with mex, so may be someone could help me please. i want to define a large array in my mex-code but at some point matlab crashes. Does somebody have an idea why or have a proposal for a solution? Many thanks! :)

Heres the code:

void mexFunction(int nlhs, mxArray *plhs[], int nrhs, const mxArray *prhs[])
{
 float  myArray[106*3*7555]; // doesnt work but works with a smaller definition

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

James Tursa 2013-4-19

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/72801-beginner-mex-array-size-too-large#answer_82845

在 MATLAB Online 中打开

Your myArray is a local variable, meaning that the memory for it is obtained from the stack. The stack for your program is typically limited in size to a much smaller amount than the heap. To get your variable allocated from the heap instead of the stack you can allocate it with one of the memory allocation functions, e.g.:

void mexFunction(int nlhs, mxArray *plhs[], int nrhs, const mxArray *prhs[])
{
 float *myArray;
 myArray = mxMalloc(106*3*7555*sizeof(*myArray));
 // insert code to use myArray
 mxFree(myArray);
}