First time matlab user problem Matrix dimensions must agree?
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Hi,
I'm a first time matlab user and I've run into a bit of a problem I keep getting an error. Here is my sequence of codes:
derivefilter(FREQSPEC,600);
handle =
1
y =
173.0011
ans =
173.0011
filtering=applyfilter(pic1,ans);
Error using .*
Matrix dimensions must agree.
Error in applyfilter (line 3)
filteredspec=imgspec.*filter;
Here is the script "applyfilter":
function y=applyfilter(img,filter)
imgspec=fftshift(fft2(img));
filteredspec=imgspec.*filter;
y=real(ifft2(fftshift(filteredspec)));
Any help would be appreciated thanks.
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采纳的回答
Image Analyst
2013-4-23
What does derivefilter() return? You're not accepting any matrix for the filter that you can then pass in to applyfilter() instead of ans. You may need to have something like
myFilter = derivefilter(FREQSPEC,600);
filtering=applyfilter(pic1, myFilter);
but we can't tell until we know what's inside derivefilter().
6 个评论
Walter Roberson
2013-4-24
pic1 = rgb2gray(pic1); %convert to 600x600
but you also need to solve the other issues.
更多回答(2 个)
Leah
2013-4-23
imgspec and filter must have the same dimension to do a element-wise multiplications
size(imspec)
size(filter)
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Jan
2013-4-23
编辑:Jan
2013-4-23
Your code would be easier to read, if you spend the time for reading the manuals for this forum and format the code properly.
It looks like:
imgspec .* filter
cannot work, because the array sizes do not match. This is surprising, because the value of filter seems to be a scalar.
Using ans explicitly is a bad idea, because this value is very volatile and debugging can change the value. filter is not a good choice also, because this is a name of an important built-in function.
2 个评论
Jan
2013-4-24
@Azfar: Then it is the job of your supervisor to find the solution. We cannot guess how this should be fixed, because all we see is the failing code. To find a solution, one has to know the intention of the code, but wrong code cannot carry this kind of information.
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