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How to solve the error "Dimensions of arrays being concatenated are not consistent"

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Katara So
Katara So 2021-2-7
评论： Steven Lord 2021-2-7
I have data of size 170x300 and want to create a matrix for the board of Game of Life but keep getting the error:
Error using vertcat
Dimensions of arrays being concatenated are not consistent
This is my code:
load Data %which the data of size 170x300
[N,M]=size(A)
B = zeros(N,N);
v1 = zeros(1,(N+2));
v2 = zeros(M,1);
A = [v1;v2 B v2;v1];
I did the same thing for a matrix of size N = 16 where the code was:
N=16;
B = zeros(N,N);
v1 = zeros(1,(N+2));
v2 = zeros(N,1);
A = [v1;v2 B v2;v1];
which work perfectly. What do I need to do differently for the bigger matrix? All help is appreciated!

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回答（1 个）

Walter Roberson
Walter Roberson 2021-2-7
v2 = zeros(N,1);
However, if you are just going to write all over A anyhow, and you are going to do so with the all-zero values, then
A = zeros(size(A,1)+2);
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Walter Roberson
Walter Roberson 2021-2-7
At what point is it saying that i = 2 when you expect it to be 170 ?
You posted that there is an error
Error in celldestiny (line 2)
n = numneighbours(A,i,j)
but you did not show what the error is and you did not show the code for numneighbours()
Watch out, by the way, for numneighbours() vs numneighbors() . "Neighbours" is of course the correct spelling, but we in Canada are quite accustomed to the people in the USA spelling it incorrectly.

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