Extract numeric data from cell

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Baklouti Sana
Baklouti Sana 2021-2-9
评论： Jan 2021-2-9
I need to extract numbers from a cell and put them in a matrix.
My cell is expressed as following:
A={'position: [0.5418702363967896, 0.0005752428551204503, -3.834952076431364e-05, 0.0, 0.0, 0.0]'};
I tried the following example but it does not consider the e-5 .
A1 = regexp(A,'[\d*\.]*\d*','match')
A2 = [A1{:}]
out = str2double(strcat(A2{:}))
I need to get the full number to be able to make some calculations.
Thank you for help.

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采纳的回答

Mathieu NOE
Mathieu NOE 2021-2-9
hello
A = {'position: [0.5418702363967896, 0.0005752428551204503, -3.834952076431364e-05, 0.0, 0.0, 0.0]'};
A1 = regexp(char(A),'[-+]?([0-9]*[.])?[0-9]+([eE][-+]?\d+)?','match'); % extract numerical content of string
out = str2double(A1);
  2 个评论
Stephen23
Stephen23 2021-2-9
编辑：Stephen23 2021-2-9
Ran in:
More efficient than this answer:
format short G
A = {'position: [0.5418702363967896, 0.0005752428551204503, -3.834952076431364e-05, 0.0, 0.0, 0.0]'};
X = find(A{1}=='[',1);
V = sscanf(A{1}(1+X:end),'%f,')
V = 6×1
0.54187 0.00057524 -3.835e-05 0 0 0

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更多回答（1 个）

Jan
Jan 2021-2-9
A = ['position: [0.5418702363967896, 0.0005752428551204503, ', ...
'-3.834952076431364e-05, 0.0, 0.0, 0.0]'];
D = extractBetween(A, '[', ']');
data = sscanf(D{1}, '%g,')
  1 个评论
Baklouti Sana
Baklouti Sana 2021-2-9
@Jan Thank you for your response. However, I am using MATLAB 2016a and the function extractBetween is not supported.

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