Why do we need to flip the kernel in 2D convolution?
显示 更早的评论
Why do we need to flip the kernel in 2D convolution in the first place? What's the benefit of this? So, why can't we leave it unflipped? What kind of terrible thing can happen if you don't flip it?
SEE: "First, flip the kernel, which is the shaded box, in both horizontal and vertical direction"
采纳的回答
更多回答(1 个)
Image Analyst
2013-5-2
编辑:Image Analyst
2013-5-2
1 个投票
It doesn't need to be flipped, at least not by you. You pass in the array and the flipping is done internally, automatically, because that's the definition of convolution. If it didn't flip, it would be correlation, not convolution. If you flipped it before passing it into conv2(), then you'd be doing a correlation instead of a convolution because the internal flip in counteracted by your advance manual flip. If you want, you can use imfilter() or xcorr2() which do no flip internally.
3 个评论
Adnan Khan
2017-9-18
How flipping is done internally? though it is clear from the formula that it is done but how can we explain this in simple and concise words...
Image Analyst
2017-9-18
Flip it left to right using fliplr(), then flip it top to bottom with flipud().
Webi Dabuse
2020-9-29
Or you can just rotate it by 180 degrees. rot90(image,2)
类别
在 帮助中心 和 File Exchange 中查找有关 Signal Processing Toolbox 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!