matlab function in simulink
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Hi everyone
In the Simulink environment, I encountered a problem that I want to create a discrete viewer using the MATLAB function and I did this with the for-loop. The problem is that function inputs, which are discrete signals, are not arrays and will be 1 by 1. Someone can help me?
function wr = fcn(ia,ib,va,vb)
I=[1 0;0 1];
J=[0 -1;1 0];
i_a=1;
i_b=0;
psi_a=1;
psi_b=0;
wr0=0;
for i=1:length(ia)
wr=wr0+0.2*(i_a - ia(i))*psi_a;
[i_a;i_b;psi_a;psi_b] == [I+0.1 0.5*I+0.9*wr;J+1*I J*wr+0.2*I]*[i_a;i_b;psi_a;psi_b] ...
+[I*800;0*I]*[va(i);vb(i)] - [2*I-1*J;wr*I-0.2*J]*[ia(i);ib(i)];
wr0 = wr;
end
3 个评论
Walter Roberson
2021-2-27
What is that == doing there? You cannot do multiple assignments using that approach.
Also it looks like after the == you have a 2x2 array * a 4x1 array, which would be a dimension mismatch.
Mirzakhani
2021-2-27
I have a 4*4 array.let me explain on paper.I'm implementing a Leuenberger observer in Simulink using matlab function.
Mirzakhani
2021-2-27
回答（1 个）
Walter Roberson
2021-2-27
You are in a MATLAB Function Block, so you need to follow MATLAB syntax.
MATLAB does not have multiple assignment in the form
[list] Operator [list]
In order to do multiple assignment in MATLAB you need one of these forms:
1)
[list] = deal(expression, expression,...)
deal is really just a function that returns multiple outputs, copying each input to its corresponding output. Example
[a, b] = deal(3,5)
2) cell expansion
[list] = somecell{:}
example
t = {3,5}
[a, b] = t{:}
3) structure expansion
[list] = Some_struct.fieldname
example
t(1).x=3;
t(2).x=5;
[a, b] = t.x
When you have a list of values of fixed size, in my opinion you should just use straight forward individual assignments: the alternatives just make the code less clear and less efficient.
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2021-2-27
2021-2-27
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