Find values per day using a bin width.

2021 3 2
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Hi. I have an 738x2 catalog that contains days (0,1,2..etc) and earthquake magnitudes. I need to to find the magnitudes per day using a bin width i.e 2.1- 3, 3-4, 4-5, 5-6 and to store them in this format: 2.1-3 3-4 4-5
0 .... .... ....
Any help? Bellow, I attach my catalog. 1 .... .... ....

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Jan
Jan 2021-3-2
编辑：Jan 2021-3-2
I do not understand, which format you want. What does the ... mean?
Days Magnitude bins
2.1-3 3-4 4-5 5-6
0 34 12 0 1
1 23 34 2 3
2 47 25 3 3

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Cris LaPierre
Cris LaPierre 2021-3-2
编辑：Cris LaPierre 2021-3-2
Ran in:

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Ran in:
A little creativity with groupsummary will get you the data you want. It allows you to group your data by day and by user-defined bin edges, each applied to just the corresponding table variables.
eq = readtable("days_magnitudes.txt");
eqT = groupsummary(eq,{'Var1','Var2'},{'none',[1 3 4 5 6]},'IncludeEmptyGroups',true,'IncludeMissingGroups',true)
eqT = 468x3 table
Var1 disc_Var2 GroupCount ____ _________ __________ 0 [1, 3) 56 0 [3, 4) 32 0 [4, 5) 2 0 [5, 6] 1 1 [1, 3) 61 1 [3, 4) 6 1 [4, 5) 0 1 [5, 6] 0 2 [1, 3) 37 2 [3, 4) 15 2 [4, 5) 1 2 [5, 6] 1 3 [1, 3) 21 3 [3, 4) 5 3 [4, 5) 0 3 [5, 6] 0
If you want the output to be a matrix with a row for each data, and a column for each bin, you can do that in the following way.
out = [unique(eq.Var1), reshape(eqT.GroupCount,4,[])']
out = 117×5
0 56 32 2 1 1 61 6 0 0 2 37 15 1 1 3 21 5 0 0 4 15 1 0 0 5 12 0 0 0 6 11 2 0 0 7 12 4 0 0 8 12 1 0 0 9 6 0 0 0

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Thank you, but I have a 2015 version. So any alternative for groupsummary ?
Cris LaPierre
Cris LaPierre 2021-3-2
You'll need alternatives for much of the code, as readtable will behave differently, and strings were not yet supported. You might be able to use findgroups and splitapply (introduced in R2015b), perhaps in conjunction with discretize (introduced in R2015a). Sorry, but I don't have a 2015 version installed to test it for you.
Any chance you can update? Or use MATLAB Online?

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