Generate cell of random numbers with same size arrays

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Riccardo Zabatta
Riccardo Zabatta 2021-3-6
评论： Riccardo Zabatta 2021-3-8
Hello!
I'd like to generate a 3x2 cell, whose arrays are all matrices 5x100 of random numbers.
I am a bit struggling with it, despite I think is quite easy to do.
Any suggestion?
Thanks
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Riccardo Zabatta
Riccardo Zabatta 2021-3-6
What I've tried so far is something derived I found on the community.
%lowercase variables are MATRICES, capitals are CELLS
%define a, matrix 18x100 of random integers
a = randi(50,18,100);
%define A, cell derived from a, where its 18 rows are splitted in three 6-rows arrays
A = mat2cell(a,[6,6,6],100);
So, this way A results to be a 3x1 cell.
But I need it to be 3x2, so I tried to define B:
%ATTEMPT 1)
%define B, cell derived from matrix a, where its "structure" is splited in six 18x50 arrays
B = mat2cell(a,([6,6,6],50),([6,6,6],50));
But this does not work bc of syntax
I solved my problem by defining, same as I did for A, a new 3x1 cell called C and then I defined my definitive cell (let's call it D):
%ATTEMPT 2)
%define a,b matrices 18x100 of random integers
a = randi(50,18,100);
b = randi(50,18,100);
%define A,B cells derived from a,b respectively.
% Where their 18 rows are splitted in three 6-rows arrays
A = mat2cell(a,[6,6,6],100); % 3x1 cell
B = mat2cell(b,[6,6,6],100); % 3x1 cell
E = [A,B];
But still I am wondering if there is a way to get success from attempt 1)
Jan
Jan 2021-3-6
A a 3x2 cell with containing 5x100 matrices, a 15 x 200 random matrix is needed. Why do you create a 18x100 matrix?

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采纳的回答

Jan
Jan 2021-3-6
编辑：Jan 2021-3-6
Creating a large array only to split it into parts needs more RAM than creating the random matrices in parts directly:
C = cell(3, 2);
for k = 1:numel(C)
C{k} = randi(50, 5, 100);
end
If mat2cell is required for any reasons:
a = randi(50, 15, 200);
A = mat2cell(a, [5, 5, 5], [100, 100])

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John D'Errico
John D'Errico 2021-3-6
编辑：John D'Errico 2021-3-6
Ran in:
Simple enough.
A = rand(15,200);
B = mat2cell(A,repmat(5,3,1),repmat(100,1,2));
size(B)
ans = 1×2
3 2
size(B{1,1})
ans = 1×2
5 100
class(B{1,1})
ans = 'double'
So B is a cell array of size 3x2.
Each element of B is a regular double precision array, of size 5x100. You can put whatever you kind of random numbers you wish into the original array A.

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