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getting "Index exceeds matrix dimensions." Can anyone explain?

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siddhesh rane
siddhesh rane 2013-5-21
function [ coordinates ] = readSTL1( filename,k)
% reads ASCII STL file and gives coordinates of vertices.
%filename-name of file(test.txt),k- number of rows in cell.
fid=fopen(filename);
C=textscan(fid,'%s');
%reads file and generates cell.
m = 11;
i = 1;
coordinates = zeros(4455,1);
while(m < (k-3))
j = 1;
while (j < 4)
l = 1;
while(l<4)
coordinates(i) = C(m);
l = l+1; % makes sure loop runs thrice.
m = m+1; % access corresponding row from cell'C'.
i = i+1; % row number in output matrix.
end
m = m+1;
j = j+1;
end
m = m+10;
end
end

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回答（2 个）

Walter Roberson
Walter Roberson 2013-5-21
Are you sure that is your code? textscan() returns a cell array, so your C is a cell array and thus C(m) is a 1x1 cell array (which has a string inside it), but you cannot assign a cell array into a numeric array (you initialized coordinates as zeros() which is numeric).
Even if you were to change it to C{m} then C{m} would be a string, most likely of multiple characters, and assigning multiple characters into a single numeric location is not going to work.
When you use textscan with a '%s' format, the input will be divided up into (whitespace delimited) strings with line boundaries treated the same as whitespace, so C will contain one location per string. e.g.,
fizz 19 39
bar
would return
{'fizz'; '19'; '39'; 'bar'}
You assume in your code that m starts from 11, so your code that accesses C(m) is going to fail of there were not at least 11 strings in the file.
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siddhesh rane
siddhesh rane 2013-5-21
编辑：siddhesh rane 2013-5-21
Yes..the cell has both numerical and text datas..i wrote this code to separate numerical data from text..numerical data repeats itself in certain sequence.so i have to copy data from those rows and create coordinates matrix .rowise sequence of occurance of data is {[(11,12,13)(15,16,17)(19,20,21)][(32,33,34)(36,37,38)(40,41,42)]}..for accessing thows rows i used three while loops..And as my cell will have atleast 11 columns i guess that wont be a problem.
Walter Roberson
Walter Roberson 2013-5-21
At the command line, give the command
dbstop if error
then run the program. When it stops at the error you indicated, examine size(C) and the value of m .

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Iain
Iain 2013-5-21
If you know the indices of where the data is, you can instead do:
Indices = [ 11 12 13 15 16 17 19 20 21 32 33 34 36 37 38 40 41 42];
for i = 1:numel(Indices)
coordinates(i) = C{Indices(i)};
end
The error occurs because your "m" is larger than the number of elements in C.

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