Fractal in matlab and image segmentation

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Rosida Octavia Sitorua
评论： Keerthi Reddy 2023-7-12
Here is segmentation process and at the last i wanna count the fractal dimension of the last figure. But it goes error. Can somebody help me to fix this. Thanks
image_folder = 'C:\Users\ADMIN\Matlab\Implementasi\Week7-1\output';
outfolder = 'C:\Users\ADMIN\Matlab\Implementasi\Week7-1\segmentasi';
if ~isdir(outfolder); mkdir(outfolder); end
files = dir(fullfile(image_folder, '*.jpg'));
%I presume it has the variable map in it
for iFiles = 1:numel(files)
thisfilename = fullfile(files(iFiles).folder,files(iFiles).name);
[~, basename, ext] = fileparts(image_folder);
citra = imread(thisfilename);
%change to grayscale
grayimg = rgb2gray(citra);
figure, fig2=imshow(grayimg);
%change to green channel
green_channel = citra(:,:,2);
figure, fig3=imshow(green_channel);
%change to CLAHE (Contrast Limited Adaptive Histogram Equalization)
CLAHE = adapthisteq(green_channel);
figure, fig4=imshow(CLAHE);
ER = edge(CLAHE, 'canny');
EG = edge(CLAHE, 'canny');
EB = edge(CLAHE, 'canny');
anyedge = ER | EG | EB;
figure, fig5=imshow(anyedge)
size(fig5)
% fig = figure;
outfile = fullfile(outfolder, sprintf('%s-coba-%03d.jpg', basename, iFiles));
saveas(fig5, outfile);
% yang dihitung dimensinya yaitu citra hasil segmentasi
[n, r] = fboxcount(figure,'slope');
%Perhitungan dimensi
df = -diff(log(n))./diff(log(r));
%Menampilkan hasil dimensi
disp(['Df= ' num2str(mean(df(4:8)))]);
% end
end
  1 个评论
Keerthi Reddy
Keerthi Reddy 2023-7-12
Can you please provide the specific error message you are recieving? Also can you please provide which part of the code is causing the error?

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