How binary Random number generation upto n nodes ?

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ankanna
ankanna 2021-3-15
评论： Jan 2021-4-24
i was do this
clc;
clear all;
close all;
% Link is (n-1)*node/2
node = 3;
offset = 1;
L = (node-offset)*node/2;
c =2^L;
% Generate c binary values:
r = randi([0, 1], c,L);
disp(r);
output:
0 0 1
1 0 0
1 0 0
1 0 1
1 1 0
1 0 0
0 1 0
0 0 1
but i want
0 0 0
0 0 1
0 1 0
0 1 1
1 0 0
1 0 1
1 1 0
1 1 1
please help me how to generate binary random numbers up to n in order wise
  1 个评论
James Tursa
James Tursa 2021-3-15
Your current code generates random patterns. But what you want is not random at all ... it is an ordered list. Why do you write you want random output but then show a non-random ordered list as what you want?

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采纳的回答

James Tursa
James Tursa 2021-3-15
Here is how to get your stated desired output, but this is not random at all:
r = dec2bin(0:(2^L-1)) - '0';
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ankanna
ankanna 2021-4-24
n = 3;
Link=(n*(n-1))/2;
c=2^Link;
NN = toeplitz(Link+1:-1:2)
mask = logical(fliplr(diag(ones(1,Link-1),-1)));
NN(mask) = 1;
for c = 0:2^Link-1
l = bitget(c, NN)
end
the above code i generate all configuration matrix.
i need to generate all paths in this network.
please help me to generate all paths in the network
Jan
Jan 2021-4-24
This is a new question. Please ask it in a new thread.

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